如何将多个数据组合成一行

Question

我在使用SELECT sql函数时遇到问题。我正在尝试从我的表中获取数据，如下所示：

 cid    | cname   | fid | fname          | type   | status  | 
 10     | sue     | 4   | Bun            | pickup | pending | 
 10     | sue     | 10  | Lamb           | pickup | pending | 
 10     | sue     | 17  | Cheese         | pickup | pending | 
 10     | sue     | 31  | Spicy          | pickup | pending | 
 12     | lho     | 5   | crispy bun     | pickup | pending | 
 12     | lho     | 8   | Chicken        | pickup | pending | 
 12     | lho     | 17  | Cheese         | pickup | pending | 
 12     | lho     | 29  | Normal         | pickup | pending | 

我试图这样做：

 cid   | cname   | fname                               | type   | status  |
 10    | sue     | Bun, Lamb, Cheese, Spicy            | pickup | pending |
 12    | lho     | Crispy bun, Chicken, Cheese, Normal | pickup | pending |

下面是我的查询：

$query="SELECT cid, cname, cnumber, type, date, fid, status, fname,
GROUP_CONCAT(fname SEPARATOR ', ') FROM purchase GROUP BY cname,cid";

我的问题有什么解决办法吗？请帮助并非常感谢你。

Answer 1

GROUP_CONCAT已为您添加了commas，无需添加，请参阅以下内容：

$query="SELECT cid, cname, cnumber, type, date, fid, status,
GROUP_CONCAT(fname) FROM purchase GROUP BY cname,cid";