我需要在带有mousemove的图片框内画一个矩形。 没有超出边框的图片框。
向右或向下拖动对我来说很好......如何使动画反转?
我的代码如下。
Rectangle Rect = new Rectangle();
private Point RectStartPoint;
public Pen cropPen = new Pen(Color.Red, 2);
public Form1()
{
InitializeComponent();
}
private void pictureBox1_MouseDown(object sender, MouseEventArgs e)
{
RectStartPoint = e.Location;
picImagem.Invalidate();
}
private void pictureBox1_MouseMove(object sender, MouseEventArgs e)
{
if (e.Button == System.Windows.Forms.MouseButtons.Left)
{
Point tempEndPoint = e.Location;
Rect.Location = new Point(Math.Min(RectStartPoint.X, tempEndPoint.X),
Math.Min(RectStartPoint.Y, tempEndPoint.Y));
Rect = new Rectangle(
Math.Min(tempEndPoint.X, Rect.Left),
Math.Min(tempEndPoint.Y, Rect.Top),
Math.Min(e.X - RectStartPoint.X, picImagem.ClientRectangle.Width - RectStartPoint.X),
Math.Min(e.Y - RectStartPoint.Y, picImagem.ClientRectangle.Height - RectStartPoint.Y));
picImagem.Refresh();
picImagem.CreateGraphics().DrawRectangle(cropPen, Rect);
}
}
答案 0 :(得分:0)
您可以通过以下方式更正鼠标移动代码:
private void pictureBox1_MouseMove(object sender, MouseEventArgs e)
{
if (e.Button == System.Windows.Forms.MouseButtons.Left)
{
Point tempEndPoint = e.Location;
var point1 = new Point(
Math.Max(0, Math.Min(RectStartPoint.X, tempEndPoint.X)),
Math.Max(0, Math.Min(RectStartPoint.Y, tempEndPoint.Y)));
var point2 = new Point(
Math.Min(this.picImagem.Width, Math.Max(RectStartPoint.X, tempEndPoint.X)),
Math.Min(this.picImagem.Height, Math.Max(RectStartPoint.Y, tempEndPoint.Y)));
Rect.Location = point1;
Rect.Size = new Size(point2.X - point1.X, point2.Y - point1.Y);
picImagem.Refresh();
picImagem.CreateGraphics().DrawRectangle(cropPen, Rect);
}
}
在上面的代码中,我们首先规范化矩形的开始和结束,并使矩形的边界开始和结束。然后我们画它。