我要做的是比较两个阵列" similarBands"和#34; artistsArray"。我想记下两个数组中发生的每个匹配(这是我创建计数器背后的逻辑)。我正在寻找的最终结果是一个新的对象数组(称为newMatchingArray)这两个数组的所有匹配,它将采用name属性和matches属性(表示有多少匹配)。
该功能现在可以正确找到匹配但不会增加"计数器"在每场比赛中,它都停在2.我对JS和AJAX都很陌生,很抱歉显而易见的问题/缺乏技术细节。谢谢!
$scope.getBandsLikeThisBand = function(){
$.ajax({
async: false,
type: 'Get',
url: 'https://api.spotify.com/v1/artists/' + $scope.bandId + '/related-artists',
success: function(data){
console.log($scope.allTheArtists);
$scope.similarBandsArray = data.artists;
$scope.similarMathesArray = [];
$scope.newMatchingArray = [];
for(var i = 0; i < $scope.similarBandsArray.length; i ++){ //going through every related artist from the search
var counter = 0;
for (var x = 0; x < $scope.allTheArtists.length; x ++){ //going through every artist in the allTheArtistsArray
if($scope.similarBandsArray[i].name === $scope.allTheArtists[x].name){
counter ++;
if (counter > 0){
var toBeAddedToMutual = {
name: $scope.similarBandsArray[i],
count: counter
};
$scope.newMatchingArray.push(toBeAddedToMutual);
}
}
if($scope.soManyObjects && $scope.soManyObjects.amount > 0 ){
$scope.bigBoyArray.push($scope.soManyObjects.name + "and their count is" + ($scope.soManyObjects.amount + 1));
}
}
}
for(var j = 0; j < $scope.similarBandsArray.length; j ++){
$scope.allTheArtists.push($scope.similarBandsArray[j]);
}
}
});
};
答案 0 :(得分:0)
当您找到第一个匹配项时,counter
变为1.您创建一个对象toBeAddedToMutual
并将其插入到数组中。如何将计数作为任何其他值?
您的意思是将第二个if-block
移出第一个if-block
吗?
var counter = 0;
for (var x = 0; x < $scope.allTheArtists.length; x ++){
if ($scope.similarBandsArray[i].name === $scope.allTheArtists[x].name){
counter ++;
}
if (counter > 0) {
var toBeAddedToMutual = {
name: $scope.similarBandsArray[i],
count: counter
};
$scope.newMatchingArray.push(toBeAddedToMutual);
}
....
正如@FernandoPinheiro建议的那样,您可以使用lambda表达式缩短代码。
angular.forEach($scope.similarBandsArray, function(band) {
var matches = $scope.allTheArtists.filter(function(artist) {
return band.name === artist.name;
});
if (matches.length) {
$scope.newMatchingArray.push({
name: band, // maybe you mean band.name
count: matches.length
});
}
....
});
答案 1 :(得分:-1)
查看此库:https://lodash.com/
它具有您的算法可能需要的所有功能,例如数组,过滤器等之间的差异。