在选项卡之间切换并关闭窗口中的选项卡会产生错误

时间:2015-10-07 13:46:43

标签: python python-2.7 selenium selenium-webdriver web-scraping

她是我的代码基本上做的(或者我正在尝试做)。打开一个窗口,从页面打开一个链接,从页面中获取一些数据并关闭选项卡。问题在于关闭标签。再次打开第二个链接并再次执行相同的操作。

  link.send_keys(Keys.CONTROL + 'w')
  File "C:\Python27\lib\site-packages\selenium\webdriver\remote\webelement.py", line 323, in send_keys
    self._execute(Command.SEND_KEYS_TO_ELEMENT, {'value': typing})
  File "C:\Python27\lib\site-packages\selenium\webdriver\remote\webelement.py", line 404, in _execute
    return self._parent.execute(command, params)
  File "C:\Python27\lib\site-packages\selenium\webdriver\remote\webdriver.py", line 195, in execute
    self.error_handler.check_response(response)
  File "C:\Python27\lib\site-packages\selenium\webdriver\remote\errorhandler.py", line 170, in check_response
    raise exception_class(message, screen, stacktrace)
StaleElementReferenceException: Message: Element belongs to a different frame than the current one - switch to its containing frame to use it


from selenium import webdriver
from selenium.common.exceptions import NoSuchElementException
from selenium.webdriver.common.keys import Keys
import time
from lxml import html
import requests
import xlwt

browser = webdriver.Firefox() # Get local session of firefox

# 0 wait until the pages are loaded
browser.implicitly_wait(3) # 3 secs should be enough. if not, increase it

browser.get("http://ae.bizdirlib.com/taxonomy/term/1493") # Load page
links = browser.find_elements_by_css_selector("h2 > a")

def test():#test function
    elems = browser.find_elements_by_css_selector("div.content.clearfix > div > fieldset> div > ul > li > span")
    browser.implicitly_wait(3) # 3 secs should be enough. if not, increase it
    for elem in elems:
        print elem.text
    elem1 = browser.find_elements_by_css_selector("div.content.clearfix>div>fieldset>div>ul>li>a")
    browser.implicitly_wait(3) # 3 secs should be enough. if not, increase it
    for elems21 in elem1:
        print elems21.text
    return


for link in links:
    link.send_keys(Keys.CONTROL + Keys.RETURN)
    link.send_keys(Keys.CONTROL + Keys.PAGE_UP)
    browser.switch_to_window(browser.window_handles[-1])
    test() # Want to call test function
    browser.implicitly_wait(3) # 3 secs should be enough. if not, increase it
#    browser.quit()
    browser.switch_to_window(browser.window_handles[0])
    link.send_keys(Keys.CONTROL + 'w')
#    browser.switch_to_window(browser.window_handles[0])

1 个答案:

答案 0 :(得分:1)

  1. 当您处理多个窗口和标签时,会使用switch_to_window功能。因此,使用该功能是无用的。根据这个link,到目前为止,Selenium官方不支持标签

  2. 执行link.send_keys(Keys.CONTROL + 'w')时,请注意link元素不属于显示的当前选项卡。因此,您应该从当前选项卡中选择一个随机元素,然后调用send_keys函数。

  3. 您的for应该是这样的:

    for link in links:
        link.send_keys(Keys.CONTROL + Keys.RETURN)
        link.send_keys(Keys.CONTROL + Keys.PAGE_UP)
        test()
    
        #Here, 'r' is the random element
        r = browser.find_element_by_css_selector("h2 > a")
        r.send_keys(Keys.CONTROL + 'w')