这里是我想在php数组中做的,以下是json格式:
JSON
{
"suggestions": [
{ "value": "Alex - alex@email.com", "data": {"id": 1, "name": Alex } },
{ "value": "John - john@email.com", "data": {"id": 2, "name": John } },
{ "value": "Diaz - diaz@email.com", "data": {"id": 3, "name": Diaz } }
]
}
在我的php数组中查询结果:
array(
0 => array('id'=>'1' 'email'=>'alex@email.com', 'name'=>'Alex'),
1 => array('id'=>'2' 'email'=>'john@email.com', 'name'=>'John'),
2 => array('id'=>'3' 'email'=>'diaz@email.com', 'name'=>'Diaz')
);
您是否知道如何将我的php数组转换为JSON格式?
答案 0 :(得分:0)
这可以帮助您获得JSON格式
foreach($query as $key => $val){
$json[$key]['value'] = $val['name']." - ".$val['email'];
$json[$key]['data']["id"] = $val['id'];
$json[$key]['data']["name"] = $val['name'];
}
echo json_encode($json);
答案 1 :(得分:0)
你可以简单地使用json_encode();功能。
json_encode($array);
答案 2 :(得分:0)
foreach ($your_array as $key => $val) {
foreach ($val as $k => $v) {
if ($v == 'email') {
//get the value of 'email' key in 'value'
$newArr['suggestions']['value'] = current($v);
}
else {
//if value is not email push it in 'data' key
$newArr['suggestions']['data'] = $v;
}
}
}
//lastly encode the required array
echo json_encode($newArr);