Question

希望你们都做得很好。

我需要将XML-feed从网站导入我的SQL Server数据库。我对XML知之甚少。

饲料结构有点复杂。以下是该文件的示例：

<line_feed>
<FeedTime>1279519582927</FeedTime>
<lastContest>4103839</lastContest>
<lastGame>58629754</lastGame>
<events>
<event>
    <event_datetimeGMT>2010-07-19 21:30</event_datetimeGMT>
    <gamenumber>174087393</gamenumber>
    <sporttype>Tennis</sporttype>
    <league>abc</league>
    <participants>
        <participant>
            <participant_name>R. Ram</participant_name>
            <contestantnum>4303</contestantnum>
            <rotnum>4303</rotnum>
            <visiting_home_draw>Visiting</visiting_home_draw>
        </participant>
        <participant>
            <participant_name>K. Beck</participant_name>
            <contestantnum>4304</contestantnum>
            <rotnum>4304</rotnum>
            <visiting_home_draw>Home</visiting_home_draw>
        </participant>
    </participants>
    <periods>
        <period>
            <period_number>0</period_number>
            <period_description>Game</period_description>
            <periodcutoff_datetimeGMT>2010-07-19 21:30</periodcutoff_datetimeGMT>
            <period_status>I</period_status>
            <period_update>open</period_update>
            <spread_maximum>250</spread_maximum>
            <moneyline_maximum>1500</moneyline_maximum>
            <total_maximum>250</total_maximum>
            <moneyline>
                <moneyline_visiting>135</moneyline_visiting>
                <moneyline_home>-146</moneyline_home>
            </moneyline>
        </period>
        <period>
            <period_number>0</period_number>
            <period_description>Game</period_description>
            <periodcutoff_datetimeGMT>2010-07-19 21:30</periodcutoff_datetimeGMT>
            <period_status>I</period_status>
            <period_update>open</period_update>
            <spread_maximum>250</spread_maximum>
            <moneyline_maximum>250</moneyline_maximum>
            <total_maximum>250</total_maximum>
            <spread>
                <spread_visiting>2</spread_visiting>
                <spread_adjust_visiting>101</spread_adjust_visiting>
                <spread_home>-2</spread_home>
                <spread_adjust_home>-118</spread_adjust_home>
            </spread>
            <total>
                <total_points>22.5</total_points>
                <over_adjust>-108</over_adjust>
                <under_adjust>-108</under_adjust>
            </total>
        </period>
        <period>
            <period_number>1</period_number>
            <period_description>1st Set</period_description>
            <periodcutoff_datetimeGMT>2010-07-19 21:30</periodcutoff_datetimeGMT>
            <period_status>I</period_status>
            <period_update>open</period_update>
            <spread_maximum>5000</spread_maximum>
            <moneyline_maximum>250</moneyline_maximum>
            <total_maximum>5000</total_maximum>
            <moneyline>
                <moneyline_visiting>114</moneyline_visiting>
                <moneyline_home>-133</moneyline_home>
            </moneyline>
        </period>
    </periods>
</event>
</events>
</line_feed>

您可以帮我解决一下，如何将该数据从该Feed加载到SQL Server。

请问我是否需要了解此方案的任何其他详细信息。等待你的回应。

谢谢你， PRASHANT

Answer 1

这完全取决于您要从Feed中提取的内容....

我假设您将XML存储在SQL Server变量中，如下所示：

DECLARE @input XML

此查询将枚举所有<participants>个节点并提取有关单个参与者的所有信息 - 您可以使用此信息将这些参与者插入表中：

SELECT
    Feed.Participant.value('(participant_name)[1]', 'varchar(50)') AS ParticipantName,
    Feed.Participant.value('(contestantnum)[1]', 'int') AS ContestantNum,
    Feed.Participant.value('(rotnum)[1]', 'int') AS RotNum,
    Feed.Participant.value('(visiting_home_draw)[1]', 'varchar(50)') AS VisitingHome
FROM
    @input.nodes('/line_feed/events/event/participants/participant') AS Feed(Participant)

输出：

ParticipantName ContestantNum   RotNum  VisitingHome
R. Ram                  4303        4303     Visiting
K. Beck                 4304        4304     Home

第二个查询枚举了Feed中的<period>个节点 - 再次提取了一些可用于存储在数据库表中的信息：

SELECT
    Feed.Period.value('(period_number)[1]', 'int') AS PeriodNumber,
    Feed.Period.value('(period_description)[1]', 'varchar(50)') AS PeriodDescription,
    Feed.Period.value('(period_status)[1]', 'varchar(50)') AS Status,
    Feed.Period.value('(period_update)[1]', 'varchar(50)') AS Update,
    Feed.Period.value('(moneyline_maximum)[1]', 'decimal(18,4)') AS MoneylineMaximum
FROM
    @input.nodes('/line_feed/events/event/periods/period') AS Feed(Period)

输出：

PeriodNumber   PeriodDescription   Status  Update  MoneylineMaximum
    0             Game                I     open      1500.0000
    0             Game                I     open       250.0000
    1             1st Set             I     open       250.0000

Answer 2

如果您的XML格式正确，则可以将其存储在xml类型变量中。然后，您可以使用XPath从中读取字段：

declare @xml xml
set @xml = '
<line_feed>
<PinnacleFeedTime>1279519582927</PinnacleFeedTime>
...
'

select @xml.value('(line_feed/events/event/sporttype)[1]', 'VARCHAR(8000)')

这将打印Tennis。

将网站XML-feed导入SQL Server

2 个答案: