Question

我的数组是这样的：

Array[2]
 0: Object
        StockNo: "1"
        InvoiceNo: "1234"
        MaterialName: "MaterialName1"
        PONo: "1234"
        PRNo: "2124"
        Project: "ProjectName"
        Qty: "1"
        Remarks: "Test"
        Supplier: "SupplierName"
        TotalAmount: "23"
        Type: "2"
        Unit: "23"

  1: Object 
        StockNo: "2"      
        InvoiceNo: "1234"
        MaterialName: "MaterialName2"
        PONo: "1234"
        PRNo: "2124"
        Project: "ProjectName2"
        Qty: "1"
        Remarks: "Test"
        Supplier: "SupplierName"
        TotalAmount: "23"
        Type: "2"
        Unit: "23"

并且这个2数组位于名为“inventoryList”的变量中我想让它通过我的控制器。我用了

JSON.stringify（inventoryList）

但它不起作用。

这是我的剧本：

function addSomething() {
    var dateReceived = $('#DateReceived').val();
    $.ajax({
        url: "/MyController/Create",
        type: 'post',
        dataType: 'json',
        async: false,
        data: {
            'dateReceived': dateReceived,
            'rrList': JSON.stringify(inventoryList)
        },
        success: function (data) {
            if (data.errorMessage != '') {
                alert(data.errorMessage);
            }
            else {
                window.location.href = '/MyController/Index';
            }
        }
    })
}

Answer 1

将JSON对象更改为

inventoryList=JSON.stringify({ 'inventoryList': inventoryList});

然后在您的控制器中

public void Create(DateTime dateReceived,List<object> inventoryList)
{

}

Answer 2

我认为应该有效。

在我看来，发送数据的内容类型应为application/json，async不应设置为false，因为它会破坏ajax的行为。

所以我的建议是：

function addSomething() {
    var dateReceived = $('#DateReceived').val();
    $.ajax({
        url: "/MyController/Create",
        type: 'post',
        dataType: 'json',
        contentType: 'application/json', // <----add the content type
        //async: true, // you can remove it because default is true.
        data: {
            'dateReceived': dateReceived,
            'rrList': JSON.stringify(inventoryList)
        },
        success: function (data) {
            if (data.errorMessage != '') {
                alert(data.errorMessage);
            }
            else {
                window.location.href = '/MyController/Index';
            }
        }
    })
}

Answer 3

<html>
    <head>
        <title>Ajax Json</title>
        <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.3/jquery.min.js"></script>
    </head>
    <body>
        <h1>Well Come</h1>
        <hr>
        <div id="data">Response Add Hear...!!!</div>
    </body>
    <script type="text/javascript">
        $(document).ready(function(){
            $obj1={"StockNo":"1","InvoiceNo":"1123","MaterialName":"MaterialName1"};
            $obj2={"StockNo":"1","InvoiceNo":"1124","MaterialName":"MaterialName2"};
            $obj_array=[];
            $obj_array.push($obj1);
            $obj_array.push($obj2);
            $obj_array=JSON.stringify($obj_array);
            $.ajax({
                url:'test.php',
                method:'post',
                async:false,
                data:{"test":$obj_array},
                success:function(data){
                    $("#data").html(data);
                }
            });
        });
    </script>
</html>

服务器文件

<?php
echo "<pre>";
print_r(json_decode($_REQUEST['test']));
echo "</pre>";
?>

使用JSON将一组对象传递给控制器

3 个答案: