Question

我能够以缩小的方式打印出我的图案，但是如何以相反的方式将其打印出来以便扩展？

import time

pattSize = int(input("input pattern size: "))

while pattSize < 3:  
    pattSize = int(input("input pattern size: "))
    print("warning: pattern size should be at least 3!") 

if pattSize%2 == 0:
    steps = (2*(pattSize/2)) + 1;
else:
    steps = (2*((pattSize + 1) / 2))  + 1;

counter = 0
while True:
    step = (counter%steps)
    for i in range(pattSize):
        line = "";
        for j in range(pattSize):
            if (step <= 4):
                if (i == (0 + step) or j == (0 + step) ) and (i > (-1 + step) and j > (-1 + step)) and (i < (pattSize - step) and j < (pattSize - step)):
                    line += "*"
                elif (i == (pattSize - (1 + step)) or j == (pattSize - (1 +  step)) ) and (i > (-1 + step) and j > (-1 + step)) and (i < (pattSize - step) and j < (pattSize - step)):
                    line += "*"
                else:
                    line += "."

        print(line)

    counter += 1
    time.sleep(1);

对于5的输入，模式缩小如下。现在我想扭转它，这就是增长模式。

*****
*...*
*...*
*...*
*****
.....
.***.
.*.*.
.***.
.....
.....
.....
..*..
.....
.....
.....
.....
.....
.....
.....

Answer 1

删除了一些不必要的代码。

为什么在寻找用户输入时突破while循环。
if (step <= 4):？
不需要柜台等。

代码：

pattSize = int(input("input pattern size: "))

while pattSize < 3:  
    print("warning: pattern size should be at least 3!") 
    pattSize = int(input("input pattern size: "))

steps = int(math.ceil(pattSize/2)) 
steps = list(range(steps))

def pattern(steps):    
    for step in steps:
        for i in range(pattSize):
            line = ""
            for j in range(pattSize):
                    if (i == (0 + step) or j == (0 + step) ) and (i > (-1 + step) and j > (-1 + step)) and (i < (pattSize - step) and j < (pattSize - step)):
                        line += "*"
                    elif (i == (pattSize - (1 + step)) or j == (pattSize - (1 +  step)) ) and (i > (-1 + step) and j > (-1 + step)) and (i < (pattSize - step) and j < (pattSize - step)):
                        line += "*"
                    else:
                        line += "."

            print(line)    
        time.sleep(0.1)

while True:
    pattern(steps)
    pattern(steps[1:-1][::-1])

尝试使用50号尺寸看起来很静，看起来很酷：）

如何反转打印图案

1 个答案: