Question

这是我的问题：输出以下内容表示：

欢迎学生＃1，您的门票是＃1001

欢迎学生＃2，您的门票是＃1002

...

欢迎学生＃10，您的机票是＃1010

这就是我到目前为止所做的：

#--RAFFLE TICKETS--#
for i in range(1001,1011):  #since 1001 is inclusive and 1011 is exclusive 
    for j in range(1,11):
        print("Welcome student #",j,"your ticket is #"+str(i))
    break

但我无法获得最多10张票数。我需要同时使用（for和while循环）。提前感谢您提供的任何帮助！

Answer 1

为什么需要嵌套循环？

>>> for i in range(1, 11):
...     print('Welcome student # {} your ticket is #10{:02d}'.format(i, i))
...     
Welcome student # 1 your ticket is #1001
Welcome student # 2 your ticket is #1002
Welcome student # 3 your ticket is #1003
Welcome student # 4 your ticket is #1004
Welcome student # 5 your ticket is #1005
Welcome student # 6 your ticket is #1006
Welcome student # 7 your ticket is #1007
Welcome student # 8 your ticket is #1008
Welcome student # 9 your ticket is #1009
Welcome student # 10 your ticket is #1010

Answer 2

使用for循环：

list

使用while循环：

for i in range(1,11):
    print ( "Welcome student #", i ,"your ticket is #" , 1000+i)

Answer 3

试试这个！

else if (type.equals("gas"))

或者，作为一个while循环：

for i in range(1001,1011):
     print("Welcome student #"+str(i-1000) + " your ticket is #"+str(i))

Answer 4

您也可以使用字典：

>>> a = range(1001,1011)
>>> b = {x:a[x] for x in range(len(a))}
>>> for key, val in b.items():
        print ("Welcome student #"+ str(key+1) + " your ticket is #"+str(val))

欢迎学生＃1您的机票是＃1001
欢迎学生＃2你的机票是＃1002
欢迎学生＃3您的机票是＃1003
欢迎学生＃4你的门票是＃1004
欢迎学生＃5您的机票是＃1005
欢迎学生＃6你的机票是＃1006
欢迎学生＃7您的机票是＃1007
欢迎学生＃8您的机票是＃1008
欢迎学生＃9你的机票是＃1009
欢迎学生＃10您的门票是＃1010

如何在python（for和while循环）中解决这个问题？

4 个答案: