如何从＆＃39;案例中计算＆＃39;条件

Question

我希望有人可以提供帮助，关于我的案例：

如何从我的情况算起我的SQL代码中的条件如下：

SELECT CASE WHEN datediff( b.`DATE` , A.`SUBMIT_DATE` ) >3
THEN 'NOK'
ELSE 'OK'
END AS
STATUS FROM complaint a
LEFT JOIN handling b ON a.cid = b.cid

Answer 1

SELECT
   CASE
        WHEN datediff( b.`DATE` , A.`SUBMIT_DATE` ) >3 THEN 'NOK'
        ELSE 'OK'
   END AS STATUS 
FROM complaint a
LEFT JOIN handling b ON a.cid = b.cid 
GROUP BY CASE 
            WHEN datediff( b.`DATE` , A.`SUBMIT_DATE` ) >3 THEN 'NOK'
            ELSE 'OK'
         END

或者，您可以将状态（OK，NOK）转换为不同的列：

SELECT   
   COUNT CASE WHEN datediff( b.`DATE` , A.`SUBMIT_DATE` ) >3 THEN 1 END) AS 'NOK',
   COUNT CASE WHEN datediff( b.`DATE` , A.`SUBMIT_DATE` ) <=3 THEN 1 END) AS  'OK' 
FROM complaint a LEFT JOIN handling b ON a.cid = b.cid

Answer 2

它应该是这样的：D哈哈：

Select status,count(*)
From 
(
SELECT CASE WHEN datediff( b.`DATE` , A.`SUBMIT_DATE` ) >3 THEN 'NOK' ELSE 'OK' END AS STATUS FROM complaint a LEFT JOIN handling b ON a.cid = b.cid
) a
Group by status

Answer 3

尝试以下查询 -

SELECT CASE WHEN DATEDIFF( b.`DATE` , A.`SUBMIT_DATE` ) >3 THEN 'NOK' ELSE 'OK' END AS mystatus, 
SUM(IF(DATEDIFF( b.`DATE` , A.`SUBMIT_DATE` ) >3,1,0)) AS cnt 
FROM complaint a
LEFT JOIN handling b ON a.cid = b.cid 
GROUP BY mystatus;