最近，我开始在大学里学习C ++，并被要求制作一个循环序列的＆＃34; *＆＃34;顺序如下：
*
***
*****
*******
*********
*********
*******
*****
***
*
[无限期地继续直到它变为x行，其中x在开始时指定]
如果您需要可视化，我是如何做到的：
#include<iostream>
#include<windows.h>
using namespace std;
int main() {
int hFar=0; //Variable that will be used to find out how many parts into the sequence the user would like to travel.
unsigned long int fibSequenceA = 0; //Unsigned doesn't overflow as easilly. This is the first value of the fibunacci sequence, it's defined as 0 to start.
unsigned long int fibSequenceB = 1; // Second Value of fibbunacci sequence. Defined at 1 to start.
int sPart = 1;//Used for the * sequence, it is the part of the sequence that the loop is on. It changes dynamically by either +2 or -2 every loop.
int cValue = 0;// also for the * sequence, it is the current number of * typed.
int sDirection = 0; // used to change from subtracting 2, and adding 2.
int redo = 1; // used to ensure that every 9 and every 1 the sequence repeats that number a second time. Starts at one because the sequence starts with only 1 single * rather then 2 *.
cout << "How far into the second sequence would you like to travel?" << endl; //Requests how far into the * sequence you'd like to go.
cin >> hFar; //inputs answer into variable.
for(int i = 0; i < hFar; i++ ) {//begins for statement. Notice there's no hfar/2. There will only be 1 output per line now.
while(cValue < sPart) { //Basic while loop to input the ammount of * on the current line. Works by adding a * depending on what part of the sequence it is.
cout << "*"; //self explainitory.
cValue++; //raises the cValue in order to keep track of the current number of *. Also prevents infinite loop.
}
if(sPart == 9 && redo == 0) { //Checks if the sequence part is 9, meaning that the value begins to reduce to 1 again. But first, it must repeat 9 to keep with the sequence.
sDirection = 3; //sets the direction to 3 to make sure that the value of sPart stays at 9, instead of reducing by 2.
redo = 1; //resets the redo.
cValue = 8; //changes the value of the current number of 8. Not sure if this is important, It gets done again later to make sure anyway.
sPart = 9; //Changes the sPart to 9, the needed number of *. Also redone later, but to make sure, I kept this here.
}
else if(sPart == 9 && redo == 1) { // if the sequence has already redone the 9th *
sDirection = 1; //sets the direction to 1; The sequence will reverse.
redo = 0; //returns redo to 0 to ensure that next time it reaches 1, it repeats the 1 * again.
}
else if(sPart == 1 && redo == 0) { //when the value reaches one for the second time, it needs to repeat that value.
sDirection = 3; //sets the direction to 3 again to stop the change.
redo = 1; //resets the redo.
cValue = 0;//also might be redundant.
}
else if(sPart == 1 && redo == 1) { // stops the duplicate number of *
sDirection = 0; //sets the direction to +2 again.
redo = 0;//resets the redo.
}
Sleep(50);
cout << endl; //adds a new line. This ensures that we get a new line after every part rather then 900 * on one line.
if(sDirection == 0) { //if the direction is positive.
sPart += 2; //adds 2 to the spart to keep with the sequence.
cValue = 0; //resets the cValue to 0 so the while statement works again.
}
else if(sDirection == 1) { //if the direction is negative
sPart -=2; //subtracts 2 from the spart to keep with the sequence.
cValue = 0; //resets the cValue to keep the while statement working.
}
else if(sDirection = 3) { //if the change is
//Could have been done differently. Could have just set the values to themselves, but it wasn't working. not sure why.
if(sPart == 9){ //if the spart is currently 9.
sPart = 9; //keeps it at 9.
cValue = 0; //resets the cValue.
}
else if(sPart == 1){ //if the spart is currently 1
sPart = 1; //keeps it at one.
cValue = 0; //resets the cValue.
}
}
}
return 1;//ends the code.
}
[对不起所有的评论，我试图确保我理解我正在做的事情，就像我说的，我正在学习:)，
在使用循环时，我最终将Sleep（）函数放入其中，以便在生成序列时产生波形效果。这让我思考，我想知道是否有可能使命令提示符像一个临时的体积可视化器。 （＆＃34; *＆＃34;该时间点的音量越高。）
所以，当我在电脑上播放一首歌时，程序会找到扬声器的总输出，然后输入一些＆＃34; *＆＃34;与该卷相关，并将继续这个直到程序结束，产生（希望）一个有趣的效果。 （如果您感到困惑，请在计算机上播放歌曲，右键单击任务栏上的扬声器图标，然后单击打开音量混音器，然后查看音量级别的变化，这是我和＃的效果类型39;正在寻找）
这可能吗？我一直在谷歌上搜索这个问题，（发现This之类的东西，我找到了很多方法来找出当前的MASTER音量，并改变它，但我正在寻找一个人听到的实际音量，而不是我的扬声器可以输出的最大音量。
这是我要做的一些事情。
int sPart = x; //x = the current output of the speaker
int cValue = 0 //the current number of "*" output
while([somecondition I'm not sure when i want the sequence to stop yet]) {
while(cValue < sPart) {
cout << "*";
cValue++;
}
cout << endl; //ends the current line, making room for the next value of the volume.
Sleep(50); //waits 50ms before finding the next volume value.
sPart = [current speaker value]; //finds the value of the speaker again.
cValue = 0; //resetting the number of "*" back to zero.
}
//I just reused the variables from my original code.
这可能吗？如果是这样，初学者会有这个能力吗？再次，如果是这样，它将如何完成？