比较字符串 - Lua

Question

我有一个文件（termino.txt），它以下列格式填写：

1. 支付账单
2. 2015-08-30T13：22：53.108Z
3. 去看医生
4. 2015-09-30T13：22：53.108Z
5. ....

所有偶数行都是RFC 3339时间戳的形式。我需要的是将今天的日期与文件的日期进行比较，看看它们是否相同。我试过这个：

  local function verifica(evt)
    local nome= ''
    local dia = ''
    local turn = 1
    local data = os.date("%x")
    local file = io.open("termino.txt", "r")
    while true do
         nome = dia
         line = file:read()
         dia = line

         if (turn %2 == 0) then

          > Here I need to compare "data" with "dia" that will receive string with RFC 3339 timestamp format.


         end
    turn ++ 
    end

end

我需要帮助才能进行比较！感谢

Answer 1

local dia = '2015-10-6T13:22:53.108Z'
-- parse date info from the RFC 3339 timestamp
local year, month, day = dia:match('(%d+)-(%d+)-(%d+)')
-- get today's date from Lua, in table format
local today = os.date('*t')
-- compare
if    tonumber(year)  == today.year
  and tonumber(month) == today.month
  and tonumber(day)   == today.day then
    -- the dates match
end