我正在寻找XmlSerializer功能,以便在我的输出XML中重新创建一些命名空间/类型信息。
所以我必须将这样的XML输出复制到旧的COM应用程序中:
<Amount dt:dt="int">500</Amount>
<StartTime dt:dt="dateTime">2014-12-30T12:00:00.000</StartTime>
我目前设置了我的属性的属性,如下所示:
[XmlElement(ElementName = "Amount", Namespace = "urn:schemas-microsoft-com:datatypes",
DataType = "int", Type = typeof(int))]
public int Amount{ get; set; }
我的XmlSerializer和Namespaces设置如下:
XmlSerializerNamespaces namespaces = new XmlSerializerNamespaces();
namespaces.Add("dt", "urn:schemas-microsoft-com:datatypes");
s.Serialize(writer, group, namespaces);
但这只会给我输出:
<dt:Amount>500</dt:Amount>
任何人都知道我哪里出错了?
答案 0 :(得分:1)
XmlElementAttribute.Namespace
指定元素本身的名称空间,而不是元素的属性。这就是您看到dt:
前缀的原因。而DataType = "int"
并不能帮助你;它用于指定多态字段的类型,并且不会自动生成dt
data type attribute。实际上,XmlSerializer
中没有自动生成XDR data type attribute values的内置功能,它们属于命名空间"urn:schemas-microsoft-com:datatypes"
。
因此,必须使用具有必要属性的包装结构手动执行此操作。以下实现是键入的而不是多态的:
public struct XdrTypeWrapper<T>
{
class XdrTypeWrapperTypeDictionary
{
static XdrTypeWrapperTypeDictionary instance;
static XdrTypeWrapperTypeDictionary() { instance = new XdrTypeWrapper<T>.XdrTypeWrapperTypeDictionary(); }
public static XdrTypeWrapperTypeDictionary Instance { get { return instance; } }
readonly Dictionary<Type, string> dict;
XdrTypeWrapperTypeDictionary()
{
// Taken from https://msdn.microsoft.com/en-us/library/ms256121.aspx
// https://msdn.microsoft.com/en-us/library/ms256049.aspx
// https://msdn.microsoft.com/en-us/library/ms256088.aspx
dict = new Dictionary<Type, string>
{
{ typeof(string), "string" },
{ typeof(sbyte), "i1" },
{ typeof(byte), "u1" },
{ typeof(short), "i2" },
{ typeof(ushort), "u2" },
{ typeof(int), "int" }, // Could have used i4
{ typeof(uint), "ui4" },
{ typeof(long), "i8" },
{ typeof(ulong), "ui8" },
{ typeof(DateTime), "dateTime" },
{ typeof(bool), "boolean" },
{ typeof(double), "float" }, // Could have used r8
{ typeof(float), "r4" },
};
}
public string DataType(Type type)
{
return dict[type];
}
}
public XdrTypeWrapper(T value) { this.value = value; }
public static implicit operator XdrTypeWrapper<T>(T value) { return new XdrTypeWrapper<T>(value); }
public static implicit operator T(XdrTypeWrapper<T> wrapper) { return wrapper.Value; }
[XmlAttribute("dt", Namespace = "urn:schemas-microsoft-com:datatypes")]
public string DataType
{
get
{
return XdrTypeWrapperTypeDictionary.Instance.DataType(typeof(T));
}
set
{
// Do nothing.
}
}
T value;
[XmlText]
public T Value { get { return value; } set { this.value = value; } }
}
然后在具有代理属性的类中使用它,如下所示:
public class TestClass
{
[XmlIgnore]
public int Amount { get; set; }
[XmlElement("Amount")]
[Browsable(false), EditorBrowsable(EditorBrowsableState.Never), DebuggerBrowsable(DebuggerBrowsableState.Never)]
public XdrTypeWrapper<int> XmlAmount { get { return Amount; } set { Amount = value; } }
[XmlIgnore]
public DateTime StartTime { get; set; }
[XmlElement("StartTime")]
[Browsable(false), EditorBrowsable(EditorBrowsableState.Never), DebuggerBrowsable(DebuggerBrowsableState.Never)]
public XdrTypeWrapper<DateTime> XmlStartTime { get { return StartTime; } set { StartTime = value; } }
[XmlIgnore]
public double Double { get; set; }
[XmlElement("Double")]
[Browsable(false), EditorBrowsable(EditorBrowsableState.Never), DebuggerBrowsable(DebuggerBrowsableState.Never)]
public XdrTypeWrapper<double> XmlDouble { get { return Double; } set { Double = value; } }
}
产生以下XML:
<TestClass xmlns:dt="urn:schemas-microsoft-com:datatypes"> <Amount dt:dt="int">101</Amount> <StartTime dt:dt="dateTime">2015-10-06T20:35:18.2308848+00:00</StartTime> <Double dt:dt="float">101.23</Double> </TestClass>
原型fiddle。