Question

我在页面上有一个包含多个选择题的表单，使用serializeArray给我一个像

这样的数组

[
  {
    name: "question1",
    value: "a"
  },
  {
    name: "question2",
    value: "a"
  },
  {
    name: "question3",
    value: "b"
  }
]

等等（每个问题都有答案选项a，b和c）。

如何计算数组中每个答案（a，b和c）的频率并将计数作为变量（在上述情况下a = 2，b = 1）？

Answer 1

你根本不需要jQuery。

var array = [
  {
    name: "question1",
    value: "a"
  },
  {
    name: "question2",
    value: "a"
  },
  {
    name: "question3",
    value: "b"
  }
]

var counts = {};

array.forEach(function(element) {
    if (!counts[element.value]) {
        counts[element.value] = 0;
    }

    counts[element.value] += 1;
});

console.log(counts);

// Output :
// {"a" : 2, "b" : 1}

Answer 2

类似的东西：

var countArray = {}

$.each(dataArray, function(index, value){
    if(countArray[value.value] == undefined)
        countArray[value.value] = 0;

    countArray[value.value]++;
});

Answer 3

试试这个：您可以迭代答案数组并将计数保持在单独的地图中，其中答案值是关键。见下面的代码 -

var answerArray = [
  {
    name: "question1",
    value: "a"
  },
  {
    name: "question2",
    value: "a"
  },
  {
    name: "question3",
    value: "b"
  }
];

var countMap = {};
$.each(answerArray, function(k, v){
   countMap[v.value] = (countMap[v.value])? (parseInt(countMap[v.value])) + 1 : 1;
});

alert(JSON.stringify(countMap));

<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.9.1/jquery.min.js"></script>

Answer 4

简单：

var answers = [
  {
    name: "question1",
    value: "a"
  },
  {
    name: "question2",
    value: "a"
  },
  {
    name: "question3",
    value: "b"
  }
]
var histogram = {};

for ( var n = 0; n <answers.length; n++ )
{
   if ( !histogram[answers[n].value] )
       histogram[answers[n].value] = 1;
   else
       histogram[answers[n].value] ++;
}

应该给：

{
   "a": 2,
   "b": 1,
}

Answer 5

紧凑型jQuery解决方案：

var count = {a: 0, b: 0, c: 0};

$(array).map(function(){
    count[this.value]++;
});

最终给你的是：

{a: 2, b: 1, c: 0}

使用jQuery计算数组中的值频率

5 个答案: