Question

示例字符串输出

[{v:5, f:'Week 1'}, {v:10, f:'Week 2'},{v:15, f:'Week 3'},{v:20, f:'Week 4'},{v:25, f:'Week 5'}]

段

function weekAxis(){

var ticks = '';
var week_count = <?php echo $chart ?>; //count number of weeks

    for(i=0; i<=week_count; i++){

        var tick_str[] = '{v:'+week_count, f:'Week' +week_count}';
    }
return ticks;

}

基于周数的所需输出

如果week_count = 5，

var ticks = [{v:5, f:'Week 1'}, {v:10, f:'Week 2'},{v:15, f:'Week 3'},{v:20, f:'Week 4'},{v:25, f:'Week 5'}]

如果week_count = 4，

var  ticks = [{v:4, f:'Week 1'}, {v:8, f:'Week 2'},{v:12, f:'Week 3'},{v:16, f:'Week 4'}]

如果week_count = 6，

var  ticks = [{v:6, f:'Week 1'}, {v:12, f:'Week 2'},{v:18, f:'Week 3'}, {v:24, f:'Week 4'}, {v:30, f:'Week 5'}, {v:36, f:'Week 6'}]

如所观察到的，v的值与计数本身相乘，并将循环直至达到周计数。同样，Week文本将增加计数器值。

如何根据周数计算上面的字符串？

Answer 1

试试这个：你可以初始化一个数组并将地图推入其中。在for循环中，使用count和i变量创建地图，如下所示。

＆＃13;

function weekAxis(){
    
    var ticks = new Array();
    var week_count = 4; //count number of weeks
    
        for(i=1; i<=week_count; i++){
            var tick_str = {};
            tick_str['v'] = ( week_count * i );
            tick_str['f'] = 'Week ' + i ;
            ticks.push(tick_str);
        }
    return ticks;
    
    }

alert(JSON.stringify(weekAxis()));

＆＃13;

Answer 2

这应该可以解决问题

function weekAxis(){
    var ticks = '',week_count = 5,tick_str = [];
    for(i=0; i<week_count; i++){
        var ex = {
            v:week_count*(i+1),
            f:'Week'+week_count
        };
        tick_str.push(ex);
    }
    return JSON.stringify(tick_str);
}

jQuery - 基于count的循环字符串数组

2 个答案: