Working Principle of Array.Sort()

Question

I am having an input array defined as follows:

  string[] inputArray = { "a", "s", "d", "f", "g", "2", "3", "34", "4", "4", "y", "a", "f", "8", "h", "m" };

When i perform Sorting over this array i am getting the output as:

{"2","3","34","4","4","8","a","a","d","f","f","g","h","m","s","y"}

1. Why the numbers comes before alphabets?

2. Is Array.Sort() performs sorting on the basics of ASCII code(ascii code of numbers are lower than letters)?

3. How the Sort order is defined if the array consist of special characters and alpha-numeric?

Answer 1

因为Array.Sort uses the default comparer才能排序。并且comparer将根据当前文化比较两个字符串（请注意，当双方都是字符串时，比较器具有故障转移机制）。这通常会根据他们的字符代码进行比较，然后数字会出现在字母之前。

Answer 2

字符串在所谓的词典排序中进行比较，这意味着您要比较两个第一个字符，如果相等则比较接下来的两个字符，依此类推。如果其中一个字符串在另一个字符串之前结束，则它首先出现。

确实比较了两个字符的数值，通常是ASCII。在ASCII表中，控制字符（不可打印）首先出现，然后是数字，大写字母，小写字母和这些组之间的特殊字符。

Answer 3

它的逻辑基于IComparable接口。因此sort方法使用的默认实现更喜欢数字到字母表。

第二：它完全基于IComparable接口，您可以在here

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