In my company front end system shows the "proper" date but when i am querying the database from embarcaderoRapid SQL it shows me date as a below (database) .
Its a problem for me as in our front end view we are not able to group results etc and i can do it in embarcadero.
But i need to understand what is the logic behind this date "transformation" ?
Any thoughts ?
Ofcourse i could mapp it as i figured out whats everymonth code but without understanding i will have to to this for every new month.
front end database
01/04/2015 00:000 1427842800000
01/04/2015 00:000 1427842800000
01/05/2015 00:000 1430434800000
01/05/2015 00:000 1430434800000
01/05/2015 00:000 1430434800000
01/06/2015 00:000 1433113200000
01/06/2015 00:000 1433113200000
01/07/2015 00:000 1435705200000
01/07/2015 00:000 1435705200000
01/08/2015 00:000 1438383600000
01/08/2015 00:000 1438383600000
EDIT:
Thank You for You response. You are near the answer.
Is there any function or a method in SQL/EXCEL to convert this timestamp to date we usually see ?
I also checked 04/01/2015 @ 12:00am (UTC) == 1427846400.
and got same results.
No sure why this is happening as my database shows 1427842800000
答案 0 :(得分:2)
I'm not sure I understand your question.
In the database you have a date stored as a timestamp, i.e. the number of seconds since 1/1/1970. In your frontend, the date is displayed as we usually see a date.
See: http://www.unixtimestamp.com/, when i'm writing this answer the date is 1444122272
.
EDIT : by the way, your frontend date must be in a specific timezone because 04/01/2015 @ 12:00am (UTC) == 1427846400
.
答案 1 :(得分:0)
DECLARE @TS bigint
Set @TS ='1427842800000'
SELECT DATEADD(MINUTE,60,DATEADD(MILLISECOND, @TS % 1000, DATEADD(SECOND, @TS / 1000, '19700101')))
修改:考虑时区
答案 2 :(得分:0)
尝试 from-unixtime()功能。官方链接为here。