Call instance method by self.method in Javascript

Question

Having such object in Javascript

     SomeClass = {
        methodOne: function(){
            if ( SomeClass.methodTwo() ){
                     doSomething();
                 }
        },
        methodTwo: function(account){
           doSomethingElse()
        }

I want to call self.methodTwo() instead of SomeClass.methodTwo() in methodOne body, like it would be in Python. How can I accomplish this?

Answer 1

Please don't use the word 'Class' in JavaScript, JS is a prototype based inheritance language, so you should write this this way:

var myPrototype = {
    methodOne: function () {
        console.log('Invoking method one');
        if (this.methodTwo()) {
            doSomething();
        }
    },
    methodTwo: function (account) {
        console.log('Inovking method two')
    }
}

var instance = Object.create(myPrototype);

You could use ES6 'class' syntactic sugar (and transpile it in ES5 for browser), sure, but I don't really like it (there is still no class in ES6, despite the new keywords).

JSFiddle demo

Answer 2

You can access the second method via this:

var SomeClass = {
    methodOne: function(){
        if(this.methodTwo){
            console.log('first');
        }
    },
    methodTwo: function(){
        console.log('second');
    }
};

In this case, this refers to the object within which the function are declared.

Answer 3

Like this?

 SomeClass = function() {
        this.methodOne = function (){
            if ( this.methodTwo('') ){
                     doSomething();
                 }
        }
        this.methodTwo = function (account){
           doSomethingElse()
        }
    }

    var instance = new SomeClass();

    alert(instance.methodOne());