我从我拥有的两张桌子中随机取客,
customer
========
id
first_name
surname
country
call_log
====
id
customer_id #FK
create_by
create_datetime
status (status for No answer is 7)
截至目前,我需要在通话记录中排除有2个无应答状态计数的客户。我试过这个
SELECT
customer.id,
customer.first_name,
customer.country
FROM
customer
WHERE
NOT EXISTS
(
SELECT 1 #I dont know what I should do here
FROM
call_log
WHERE
call_log.customer_id = customer.id AND
call_log.status = 7 AND #no answer
call_log.create_datetime BETWEEN '2015-10-06 00:00:00' AND '2015-10-06 23:59:59'
)
非常感谢任何帮助。感谢。
答案 0 :(得分:2)
让子选择返回no的数字。
SELECT
customer.id,
customer.first_name,
customer.country
FROM
customer
WHERE (SELECT count(*)
FROM call_log
WHERE call_log.customer_id = customer.id AND
call_log.status = 7 AND #no answer
call_log.create_datetime BETWEEN '2015-10-06 00:00:00'
AND '2015-10-06 23:59:59') < 2
答案 1 :(得分:0)
选择 顾客ID, customer.first_name, customer.country 从 顾客 WHERE(选择计数(*) 来自call_log WHERE call_log.customer_id = customer.id AND call_log.status = 7 AND #no answer call_log.create_datetime BETWEEN&#39; 2015-10-06 00:00:00&#39; AND&#39; 2015-10-06 23:59:59&#39;)&lt; 2