Question

from itertools import cycle
def get_pattern(n):
    for e,i in enumerate(cycle((1,2,4,8))):
        val = i*(10**(e//4))
        if val > n: return
        yield val

Answer 1

您可以使用view，

加快查询速度

概括所有查询以获得某种模式
创建数据库视图
重写所有查询
即 - a）用这个来创建一个视图 - ＆gt;

选择agen.agc_nama，sk.stk_id，sk.stk_nama，ls.lls_id，ls.pkt_id，sd.sbd_id，sd.sbd_ket，a.ang_tahun，p.pkt_nama，p.pkt_pagu，p.pkt_hps，p。 kgr_id，ls.mtd_pemilihan，ls.lls_tgl_setuju来自lelang_seleksi ls LEFT JOIN paket p ON ls.pkt_id = p.pkt_id LEFT JOIN（SELECT pa.pkt_id，pa.ang_id FROM paket_anggaran pa INNER JOIN（SELECT pkt_id，MAX（auditupdate）AS auditupdate FROM paket_anggaran GROUP BY pkt_id）pa1 ON pa1.pkt_id = pa.pkt_id AND pa1.auditupdate = pa.auditupdate） pa ON pa.pkt_id = p.pkt_id LEFT JOIN satuan_kerja sk ON p.stk_id = sk.stk_id LEFT JOIN agency agen ON agen.agc_id = sk.agc_id LEFT JOIN anggaran a ON pa.ang_id = a.ang_id LEFT JOIN sumber_dana sd ON a.sbd_id = sd.sbd_id 在哪里ls.lls_status = 1

b）然后用这个 -

SELECT e.lls_id,n.psr_id,pemenang.pagu_selesai,pemenang.nev_harga,MIN(n.nev_harga) AS penawaran,pemenang.eva_jenis FROM evaluasi e INNER JOIN nilai_evaluasi n ON e.eva_id=n.eva_id 
                                                INNER JOIN (SELECT n.psr_id,e.eva_id,ls.lls_id, p.pkt_pagu AS pagu_selesai, n.nev_harga,e.eva_jenis FROM lelang_seleksi ls
                                                                        INNER JOIN paket p ON ls.pkt_id=p.pkt_id AND ls.lls_status=1
                                                                        INNER JOIN (SELECT MAX(e.eva_versi) AS mev, e.lls_id FROM  evaluasi e INNER JOIN lelang_seleksi ls ON e.lls_id=ls.lls_id WHERE ls.lls_status=1 GROUP BY e.lls_id) me ON ls.lls_id=me.lls_id
                                                                        INNER JOIN evaluasi e ON me.lls_id=e.lls_id AND e.eva_jenis = 4::NUMERIC AND e.eva_versi=me.mev
                                                                        /*inner join workflow w on e.eva_wf_id = w.wf_id AND w.wf_state = 5::numeric */
                                                                        INNER JOIN nilai_evaluasi n ON e.eva_id = n.eva_id AND n.nev_lulus = 1::NUMERIC
                                                                        LEFT JOIN (SELECT   ls.lls_id,      
                                                    CASE
                                                        WHEN (SELECT COUNT(*) FROM jadwal j WHERE NOW() BETWEEN j.dtj_tglawal AND j.dtj_tglakhir AND j.lls_id=ls.lls_id) > 0 THEN '0'::NUMERIC
                                                        ELSE '1'::NUMERIC
                                                     END 
                                                      AS s_selesai
                                                FROM lelang_seleksi ls ORDER BY ls.lls_id DESC) tahapan ON tahapan.lls_id=ls.lls_id
                                                                        WHERE ls.lls_status=1 AND tahapan.s_selesai=1) pemenang ON e.lls_id=pemenang.lls_id AND n.psr_id=pemenang.psr_id
                                            WHERE e.lls_id=pemenang.lls_id AND n.psr_id=pemenang.psr_id
                                            GROUP BY e.lls_id,n.psr_id,pemenang.pagu_selesai,pemenang.nev_harga,pemenang.eva_jenis

c）然后用这个 -

SELECT
    COUNT(semualelang)                      AS total_paket,
    COUNT(selesailelang)                        AS total_paket_selesai,
    SUM(semualelang.pkt_pagu)                   AS total_pagu,
    SUM(selesailelang.pagu_selesai)                 AS pagu_selesai,
    SUM(selesailelang.penawaran)                    AS penawaran,
    SUM(selesailelang.pagu_selesai) - SUM(selesailelang.penawaran)  AS selisih,
    ROUND((SUM(selesailelang.pagu_selesai) - SUM(selesailelang.penawaran)) / SUM(selesailelang.pagu_selesai)  * 100::NUMERIC)   AS selisih_persen,
    date_part('YEAR', semualelang.lls_tgl_setuju)                   AS tahun_lelang
FROM() semualelang 
   LEFT JOIN ()selesailelang ON semualelang.lls_id=selesailelang.lls_id
GROUP BY date_part('YEAR', semualelang.lls_tgl_setuju)

实际上这个shouuld看起来像这样 - ＆gt;

SELECT
    COUNT(semualelang)                      AS total_paket,
    COUNT(selesailelang)                        AS total_paket_selesai,
    SUM(semualelang.pkt_pagu)                   AS total_pagu,
    SUM(selesailelang.pagu_selesai)                 AS pagu_selesai,
    SUM(selesailelang.penawaran)                    AS penawaran,
    SUM(selesailelang.pagu_selesai) - SUM(selesailelang.penawaran)  AS selisih,
    ROUND((SUM(selesailelang.pagu_selesai) - SUM(selesailelang.penawaran)) / SUM(selesailelang.pagu_selesai)  * 100::NUMERIC)   AS selisih_persen,
    date_part('YEAR', semualelang.lls_tgl_setuju)                   AS tahun_lelang
FROM semualelang_view 
     LEFT JOIN selesailelang_view ON semualelang_view.lls_id=selesailelang_view.lls_id
GROUP BY date_part('YEAR', semualelang_view.lls_tgl_setuju)

这不是正确的代码 - 你必须找到自己的方式，这只是PSEDUO流程你如何能够实现你的目标。

如何加快查询速度？

1 个答案: