Question

当我删除便利api时，出现的问题是TypeError: 'int' object is not iterable并指向此行id, = args[0] ...我将如何解决这个问题？我指定args [0]的问题是否与此Stacks问题类似？

CODE：
object.py （父类）

def retrieve_assessment_result(self, *args):
    id, owner, assessment = None, None, None
    if len(args) == 1:
        id, = args[0]
    elif len(args) == 2:
        owner, assessment = args
        print 'testa', owner, assessment, id
    else:
        raise ValueError('Value being passed is an object')
    if id is not None:
        print 'testi', id
        return self.session.query(Assessment_Result).\
        filter(Assessment_Result.id == id).one()
    elif owner is not None:
        print 'testo', owner
        return self.session.query(Assessment_Result).\
        filter(Assessment_Result.owner == owner).one()
    elif assessment is not None:
        print 'testa', assessment
        return self.session.query(Assessment_Result).\
        filter(Assessment_Result.assessment == assessment).one()

convenience.py （子类）

def retrieve_assessment_result(self, username, name):
    owner = self.retrieve_user(username)
    assessment = self.retrieve_assessment(name)
    return super(ConvenienceAPI, self).retrieve_assessment_result(owner, assessment)

问题2的回溯： （当我删除子类以单独检查ID时）

...
  File "/usr/local/lib/python2.7/site-packages/pyramid-1.5.7-py2.7.egg/pyramid/config/views.py", line 501, in _requestonly_view
    response = view(request)
  File "/Users/ack/code/venv/NotssWEB/notssweb/views/views.py", line 368, in get_assessment_result
    assessment_result = api.retrieve_assessment_result(assessment_result_id)
  File "/usr/local/lib/python2.7/site-packages/notssdb/api/object.py", line 313, in retrieve_assessment_result
    id, = args[0] # <-- this the issue? see object.py above
TypeError: 'int' object is not iterable

Answer 1

您正在使用元组分配;您正尝试将一个整数分配给目标的元组。即使只有一个目标，也需要右手表达来生成具有相同数量元素的序列。

删除逗号，删除[0]切片，或在右侧添加逗号以使其成为元组：

id = args[0]

或

id, = args

或

id, = args[0],

但后一个选项是第一个选项的效率相当低的版本。

检索方法给出TypeError：＆＃39; int＆＃39;对象不可迭代

1 个答案: