Question

我有一个简单的表单，我需要将其发送到带有参数的URL。

我们说我有一个名为令牌的参数，我想将其发送到example.com/?token=the_token

我不需要处理或获取输出，只需将其发送到此网址即可。

我怎么能这样做？我已经尝试了几个小时来使用URLCONNECTION和HTTPURLCONNECTION，但没有任何效果。

由于我尝试了很多东西而没有任何效果，我正在尝试从头开始。就是这样：

if (token.isEmpty()) {
                getGCMToken();
        } else {
            //Send the token to example.com/?token=token. The URL will add the token to my database with PHP.

        }

请不要使用DefaultHttpClient回复。它已被弃用。

尝试URLConnection（）：

if (token.isEmpty()) {
                getGCMToken();
        } else {
            //Send the tokeb to example.com/?token=token
            URLConnection connection = null;
            try {
                connection = new URL("mysite.com/send.php?id=my_id").openConnection();
            } catch (IOException e) {
                e.printStackTrace();
            }
            connection.setRequestProperty("Accept-Charset", "UTF-8");
            try {
                InputStream response = connection.getInputStream();
            } catch (IOException e) {
                e.printStackTrace();
            }
        }

Answer 1

请使用URLConnection。

URLConnection connection = new URL(url + "?" + query).openConnection();
connection.setRequestProperty("Accept-Charset", charset);
InputStream response = connection.getInputStream();

Answer 2

看，我去年建了一个完整的网络/ http通讯课程。我抄袭了处理get（s）的块：

至少导入以下内容：

import java.net.HttpURLConnection;
import java.net.URL;
import java.io.BufferedInputStream;
import java.io.DataOutputStream;
import java.io.File;
import java.io.FileInputStream;
import java.io.FileNotFoundException;
import java.io.InputStream;
import java.io.OutputStreamWriter;

try{
    String mainUrl = "<your_url>";

    String query = "?" + "<add_your_params_here>";

    URL url = new URL (mainUrl + query);

    HttpURLConnection urlConnection = (HttpURLConnection)url.openConnection();

    InputStream in = new BufferedInputStream(urlConnection.getInputStream());

    // If you want to process the response you have to do something the the in InputStream. But ommiting it here, as you said you won't use the response.   
}
catch (FileNotFoundException fnf){
        Log.e("Incorrect Url", "Resource was not found");
}
catch (Exception e){

}

请记住为Android Manifest xml文件添加INTERNET权限： android.permission.INTERNET

检查此响应是否添加了互联网权限：What permission do I need to access Internet from an android application?

将带有GET的表单发送到网址

2 个答案: