Question

我知道这是另一个类似主题的话题，但我搜索了stackoverflow，我找不到问题的答案。情况如下：我有一个webservice让我们用很多方法称它为testservice。最近我不得不添加另一个，所以我做了：

public int addPayments_p24(String sessionId, int pos_id, String amount, String currency, String title, String client, String address, String postal, String city, String country, String email, String language, String p24_sign) throws Exception {
     int last_inserted_id=0;
try {
    PreparedStatement statement = null;
    int timestamp = (int)(System.currentTimeMillis() / 1000L);
    statement = connection
                .prepareStatement(
                        "Insert into p24_strefa(pos_id,session_id,amount,currency,title,client,address,postal,city,country,email,language,p24_sign,timestamp)" +
                                "values(?,?,?,?,?,?,?,?,?,?,?,?,?,?);", statement.RETURN_GENERATED_KEYS);
        statement.setInt(1, pos_id);
        statement.setString(2, sessionId);
        statement.setString(3, amount);
        statement.setString(4, currency);
        statement.setString(5, title);
        statement.setString(6, client);
        statement.setString(7, address);
        statement.setString(8, postal);
        statement.setString(9, city);
        statement.setString(10, country);
        statement.setString(11, email);
        statement.setString(12, language);
        statement.setString(13, p24_sign);
        statement.setInt(14, timestamp);
        statement.executeUpdate();
        ResultSet rs = statement.getGeneratedKeys();
            if(rs.next())
            {
              last_inserted_id  = rs.getInt(1);
            }
    } catch (Exception ex) {
        _log.error("addpayments_p24", ex);
        throw ex;
    }
    finally {
        dispose();
    }

    return last_inserted_id;
}

然后我尝试从jsp文件中调用此方法，如下所示：

String sessionId = request.getParameter( "p24_session_id" );
String amount =  request.getParameter( "p24_amount" );
String currencys = request.getParameter("p24_currency");
String title = request.getParameter("p24_description");
String client = request.getParameter("p24_client");
String address = request.getParameter("p24_address");
String postal = request.getParameter("p24_zip");
String city = request.getParameter("p24_city");
String country = request.getParameter("p24_country");
String email = request.getParameter("p24_email");
String language = request.getParameter("p24_language");
String sign = get_sign_str(sessionId,amount,currencys);
int pos_id = 2414;
int testResponse;
    try {
        if (test== null) {
        inittest();
    }
    testResponse = test.addPayments_p24("test",2,"test","test","test","test","test","test","test","test","test","test","test");
    } 
    catch (testWebServicesExceptionException e) 
    {
        e.printStackTrace();
    }

与webservice的连接由此函数完成：

private static testWebServicesStub test;
 private synchronized void inittest() throws AxisFault {
        if (test == null) {
            String testWebServicesEndpoint = Settings
                    .gettestWebServicesEndpoint();
            test= new testWebServicesStub(testWebServicesEndpoint);
        }
    }

如您所见，我使用的是Axis2。当然我得到了错误：

The method addPayments_p24(AddPayments_p24) in the type TestWebServicesStub is not applicable for the arguments (String, int, String, String, String, String, String, String, String, String, String, String, String)

我现在第三天坐在这个问题上，我无法理解。如果有人知道发生了什么......

我差点忘了app是在apache-tomcat 7.0.34上运行的，如果它改变了什么，但我已经在另一个版本上测试了。当然，一切都被编译了多次，编译后我甚至反编译了所有内容以检查变量类型是否正确，当然它们是......

Answer 1

我会尝试删除“抛出前”;并从addPayments_p24“抛出异常”。

Answer 2

我暂时没有使用网络服务，所以我对此并不确定，但是，似乎你在两种方法之间混合，就像错误所暗示的那样，碰巧你正在调用方法

addPayments_p24(String, int, String, String, String, String, String, String, String, String, String, String, String)

它不存在于客户端，也不存在于它的接口（至少是可见的调用范围）。调用范围（在客户端中）中存在的方法是addPayments_p24(AddPayments_p24)，因此您需要使用您想要的参数(String, int, String, String, String, String, String, String, String, String, String, String, String)来实例化一个对象AddPayments_p24，不确定这个但似乎是真。

Java Stub类型中的方法不适用于参数

2 个答案: