Question

我的标准查询结果如下：

[
[id:79, accountName:a99name, layoutPathId:40, layoutPath:/etc/test.txt, dataTypeId:5, dataType:demo1,  vendorId:34,  vendorName:v21], 
[id:79, accountName:a99name, layoutPathId:41, layoutPath:/etc/test1.txt, dataTypeId:5, dataType:demo1,  vendorId:34,  vendorName:v21],
[id:79, accountName:a99name, layoutPathId:42, layoutPath:/etc/test3.txt, dataTypeId:6, dataType:demo2,  vendorId:35,  vendorName:v22]
]

现在我想将此结果集转换为JSON结构，如下所示：

    {
    "account": {
        "id": 76,
        "name": "a99name",
        "datatypes": [
            {
                "id": 5,
                "name": "demo1",
                "vendors": [
                    {
                        "id": 34,
                        "name": "v22",
                        "layouts": [
                            {
                                "layoutPath": "/etc/test3.txt",
                                "id": "42"
                            },
                            ....
                        ]
                    },
                    ......
                ]
            },
         .......
        ]
    }
}

我可以使用DTO，但从长远来看，我会制作很多DTO课程。是否有一种更简单的方法来单独使用java和groovy来实现这种复杂的结构？

Answer 1

所以，给定：

def input = [
    [id:79, accountName:'a99name', layoutPathId:40, layoutPath:'/etc/test.txt',  dataTypeId:5, dataType:'demo1',  vendorId:34,  vendorName:'v21'], 
    [id:79, accountName:'a99name', layoutPathId:41, layoutPath:'/etc/test1.txt', dataTypeId:5, dataType:'demo1',  vendorId:34,  vendorName:'v21'],
    [id:79, accountName:'a99name', layoutPathId:42, layoutPath:'/etc/test3.txt', dataTypeId:6, dataType:'demo2',  vendorId:35,  vendorName:'v22']
]

您可以手动执行此类操作＆＃34;数据操作：

def munged = [ account: [
    id: input.id.head(),
    name: input.accountName.head(),
    dataTypes: input.groupBy({it.dataTypeId}).collect { did, dataType ->
        [ id: did,
          name: dataType.dataType.head(),
          vendors: dataType.groupBy {it.vendorId}.collect { vid, vendor ->
              [ id: vid,
                name: vendor.vendorName.head(),
                layouts: vendor.groupBy { it.layoutPathId }.collect { lid, layout ->
                    [ id: lid,
                      layoutPath: layout.layoutPath.head()
                    ]
                }
              ]
          }
        ]
    }
]]

然后通过Groovy的JsonBuilder：

传递这张新地图

println new groovy.json.JsonBuilder(munged).toPrettyString()

将打印：

{
    "account": {
        "id": 79,
        "name": "a99name",
        "dataTypes": [
            {
                "id": 5,
                "name": "demo1",
                "vendors": [
                    {
                        "id": 34,
                        "name": "v21",
                        "layouts": [
                            {
                                "id": 40,
                                "layoutPath": "/etc/test.txt"
                            },
                            {
                                "id": 41,
                                "layoutPath": "/etc/test1.txt"
                            }
                        ]
                    }
                ]
            },
            {
                "id": 6,
                "name": "demo2",
                "vendors": [
                    {
                        "id": 35,
                        "name": "v22",
                        "layouts": [
                            {
                                "id": 42,
                                "layoutPath": "/etc/test3.txt"
                            }
                        ]
                    }
                ]
            }
        ]
    }
}

如何将地图列表转换为适当的JSON对象groovy / grails？

1 个答案: