我知道stdin.read_line()函数,但是我希望通过使用或者更符合python中raw_input()的内容来使我的代码更简洁。
所以我在关于vala的this讨论中发现了GNU ReadLine,但我不能在Genie中重现它。
我想模仿的python代码是:
loop = 1
while loop == 1:
response = raw_input("Enter something or 'quit' to end => ")
if response == 'quit':
print 'quitting'
loop = 0
else:
print 'You typed %s' % response
我能得到的最远的是:
[indent=4]
init
var loop = 1
while loop == 1
// print "Enter something or 'quit' to end => "
var response = ReadLine.read_line("Enter something or 'quit' to end => ")
if response == "quit"
print "quitting"
loop = 0
else
print "You typed %s", response
并尝试编译:
valac --pkg readline -X -lreadline loopwenquiry.gs
但我收到错误:
loopwenquiry.gs:7.24-7.31: error: The name `ReadLine' does not exist in the context of `main'
var response = ReadLine.read_line("Enter something or 'quit' to end => ")
^^^^^^^^
loopwenquiry.gs:7.22-7.81: error: var declaration not allowed with non-typed initializer
var response = ReadLine.read_line("Enter something or 'quit' to end => ")
^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
loopwenquiry.gs:8.12-8.19: error: The name `response' does not exist in the context of `main'
if response == "quit"
^^^^^^^^
loopwenquiry.gs:12.35-12.42: error: The name `response' does not exist in the context of `main'
print "You typed %s", response
^^^^^^^^
Compilation failed: 4 error(s), 0 warning(s)
我做错了什么?
感谢。
答案 0 :(得分:1)
正如Jens的评论所述,命名空间是Readline,而不是ReadLine。该函数也是readline,而不是read_line。所以你的工作代码是:
[indent=4]
init
while true
response:string = Readline.readline("Enter something or 'quit' to end => ")
if response == "quit"
print "quitting"
break
else
print "You typed %s", response
我注意到你使用valac --pkg readline -X -lreadline loopwenquiry.gs
进行编译,这很好。 -X -lreadline
告诉linker使用readline
库。在大多数情况下,您不需要这样做,因为有一个pkg-config文件,这些文件具有.pc
文件扩展名,其中包含所有必要信息。看起来好像有人submitted a patch将其修复到readline库。因此,使用-X -llibrary_i_am_using
应该是例外,因为大多数库都有.pc
文件。
我还使用while..break
作为无限循环,看看你是否认为这是一种稍微清晰的风格。