我想查询user_id
= 23,我还有一个表work_log
包含project_id
,user_id
,log_hours
,如下所示:< / p>
+----+------------+---------+-----------+
| id | project_id | user_id | log_hours |
+----+------------+---------+-----------+
| 1 | 23 | 23 | 2.5 |
| 1 | 3 | 23 | 3 |
| 1 | 23 | 23 | 1 |
| 1 | 24 | 23 | 3 |
| 1 | 24 | 23 | 1.5 |
| 1 | 23 | 23 | 0.5 |
+----+------------+---------+-----------+
但是现在我想要将每个结果的所有log_hours加起来:
+------------+------------------+
| project_id | sum_of_log_hours |
+------------+------------------+
| 23 | 4 |
| 3 | 3 |
| 24 | 4.5 |
+------------+------------------+
如何编写SQL语句以获得该结果?
答案 0 :(得分:7)
这应该这样做:
Select project_id, sum(log_hours) as sum_log_hours
from work_log
where user_id = '23'
group by project_id
答案 1 :(得分:1)
要显示所有带和的记录,只需删除where
条件。
SELECT project_id, sum(log_hours) AS sum_log_hours
FROM work_log GROUP BY project_id