Question

我是android的初学者关于这个主题有各种各样的问题，但对我来说并不清楚

我想在我的自定义列表适配器中将我的列表传递给片段怎么做？

public class MainActivity extends AppCompatActivity {
    List<News> newsList;

    private void selectItem(int position) {
        // update the main content by replacing fragments

        if (isOnline()) {
            newsList = requestData("http://Mywebsite.com/Ilmnews/api/news/getAllNews");
        } else {
            Toast.makeText(MainActivity.this, "Network ins't available", Toast.LENGTH_SHORT).show();
        }
        Fragment fragment = new NewsFragment();
        FragmentManager fragmentManager = getFragmentManager();
        fragmentManager.beginTransaction().replace(R.id.fragmentholder, fragment).commit();

    }

    public static class NewsFragment extends Fragment {

        public NewsFragment() {
            // Empty constructor required for fragment subclasses
        }

        @Override
        public View onCreateView(LayoutInflater inflater, ViewGroup container,
                                 Bundle savedInstanceState) {
            View rootView = inflater.inflate(R.layout.fragment_news, container, false);


            ListView newsListView = (ListView) rootView.findViewById(R.id.newsListView);

            // newsList is List of my News object    List<News> 
            newsListView.setAdapter(new MYListAdapter(getActivity(), newsList));

            return rootView;
        }
    }

}

其他示例仅适用于不适用于自定义对象的系统数据类型

Answer 1

public class MainActivity extends AppCompatActivity {
  public static List<News> newsList;
}

并在您的片段中使用，如下所示

wsListView.setAdapter(new MYListAdapter(getActivity(), MainActivity.newsList));

如何将我的自定义对象传递给片段

1 个答案: