我在swift 2.0项目中使用以下代码。我不能添加Alamofire.request虽然我添加"导入Alamofire"。我必须创建Alamofire的对象,然后通过它访问。
这是我创建对象的方式:
let manager = Alamofire.Manager.sharedInstance
manager.request(NSURLRequest(URL: NSURL(string: "http://httpbin.org/get")!))
let parameters = ["foo": "bar"]
manager.request(.POST, "url", parameters: parameters)
.responseJSON { request, response, json, error in
print("request: \(request)")
}
我是Alamofire和swift的新手。任何人都可以告诉我如何在完成处理程序中获得上述代码的响应以及为什么我不能使用Alamofire.request而不是manager.request。
答案 0 :(得分:4)
请参阅我的Post方法并希望帮助
发布方法:
/**
** POST Method for calling API
* Services gateway
* Method get response from server
* @parameter -> requestObject: request josn object ,apiName: api endpoint
* @returm -> void
* @compilationHandler -> success: status of api, response: respose from server, error: error handling
**/
static func getDataWithObject( requestObject: NSDictionary, apiName : NSString,
completionHandler:
(success : Bool, response : NSDictionary, error : ErrorType?) -> Void) {
// Make Url
let url = NSURL(string: apiName as String)
let request = NSMutableURLRequest(URL: url!)
request.HTTPMethod = "POST"
//request.setValue("application/json", forHTTPHeaderField: "Content-Type")
// Call the method to request and wait for the response
// @param ->
// @return ->
Alamofire.request(.POST, url!, parameters:requestObject as? [String : AnyObject], encoding: .JSON)
.responseJSON {responseRequest, responseResponse, responseResult in
// Switch for Success or Error
switch responseResult {
// If the API return succesfull response
case .Success(let data):
let data_ar = data as! NSDictionary
print(data_ar)
// Get the Status if 0 then error if 1 then succes
// From our server side
if let str = data_ar.valueForKey("OK") as? Bool {
// Check if the status is OK and no error from
// our server side
if ( str ) {
print("Response from Server %@", data_ar)
// Cast the response and pss to handler
// To notify
completionHandler(success: true, response:data_ar
, error:responseResult.error )
} else {
print("Error from Our Server %@", data_ar)
let str = data_ar.valueForKey("message") as! NSString
self.showAlertView(str, title: "Error From Server")
}
}
case .Failure(let data, let error):
print("Request failed with error: \(error)")
print(data)
print((error as! NSError).localizedDescription)
self.showAlertView((error as! NSError).localizedDescription, title: "Error From Server")
}
}
}
答案 1 :(得分:2)
请求并非始终使用JSON请检查您的请求:
以下是使用Alamofire和Swift 2的示例:
GET - JSON
Alamofire.request(.GET, "http://api.androidhive.info/contacts/", parameters: nil, encoding: .JSON, headers: nil).responseJSON { (req, res, json) -> Void in
print("\(res?.allHeaderFields)")
print("\(json.value!)")
}
POST - 没有JSON
Alamofire.request(.POST, "http://httpbin.org/get", parameters: ["foo": "bar"], encoding: .URL, headers: nil).response { (req, res, data, error) -> Void in
print(res)
print(data)
let dataString = NSString(data: data!, encoding:NSUTF8StringEncoding)
print(dataString)
}