答案 0 :(得分:2)
如您所述,一个简单的解决方案是简单地用直线连接点。这是代码:
public void onDraw(Canvas canvas) {
Path path = new Path();
boolean first = true;
for(Point point : points){
if(first){
first = false;
path.moveTo(point.x, point.y);
}
else{
path.lineTo(point.x, point.y);
}
}
canvas.drawPath(path, paint);
}
make sure you change your paint from fill to stroke:
paint = new Paint(Paint.ANTI_ALIAS_FLAG);
paint.setStyle(Paint.Style.STROKE);
paint.setStrokeWidth(2);
paint.setColor(Color.WHITE);
Another option is to connect the points with iterpolation using the quadTo method:
public void onDraw(Canvas canvas) {
Path path = new Path();
boolean first = true;
for(int i = 0; i < points.size(); i += 2){
Point point = points.get(i);
if(first){
first = false;
path.moveTo(point.x, point.y);
}
else if(i < points.size() - 1){
Point next = points.get(i + 1);
path.quadTo(point.x, point.y, next.x, next.y);
}
else{
path.lineTo(point.x, point.y);
}
}
canvas.drawPath(path, paint);
}
这仍然会产生一些尖锐的边缘。
如果你真的雄心勃勃,你可以按如下方式开始计算三次样条:
public void onDraw(Canvas canvas) {
Path path = new Path();
if(points.size() > 1){
for(int i = points.size() - 2; i < points.size(); i++){
if(i >= 0){
Point point = points.get(i);
if(i == 0){
Point next = points.get(i + 1);
point.dx = ((next.x - point.x) / 3);
point.dy = ((next.y - point.y) / 3);
}
else if(i == points.size() - 1){
Point prev = points.get(i - 1);
point.dx = ((point.x - prev.x) / 3);
point.dy = ((point.y - prev.y) / 3);
}
else{
Point next = points.get(i + 1);
Point prev = points.get(i - 1);
point.dx = ((next.x - prev.x) / 3);
point.dy = ((next.y - prev.y) / 3);
}
}
}
}
boolean first = true;
for(int i = 0; i < points.size(); i++){
Point point = points.get(i);
if(first){
first = false;
path.moveTo(point.x, point.y);
}
else{
Point prev = points.get(i - 1);
path.cubicTo(prev.x + prev.dx, prev.y + prev.dy, point.x - point.dx, point.y - point.dy, point.x, point.y);
}
}
canvas.drawPath(path, paint);
}
此外,我发现您需要更改以下内容以避免重复的动作事件:
public boolean onTouch(View view, MotionEvent event) {
if(event.getAction() != MotionEvent.ACTION_UP){
Point point = new Point();
point.x = event.getX();
point.y = event.getY();
points.add(point);
invalidate();
Log.d(TAG, "point: " + point);
return true;
}
return super.onTouchEvent(event);
}
并添加dx&amp; dy值为Point类:
class Point {
float x, y;
float dx, dy;
@Override
public String toString() {
return x + ", " + y;
}
}
这会产生平滑的线条,但有时必须使用循环连接点。此外,对于长时间的绘图会话,计算量也会增加。
希望有助于...有趣的东西可以玩。
修改
我汇总了一个展示这些不同技术的快速项目,包括Square的suggessted签名实现。享受:https://github.com/johncarl81/androiddraw
答案 1 :(得分:0)
您可以使用图表库,例如mpandroidchart
:https://github.com/PhilJay/MPAndroidChart
在移除标签和网格时绘制线图。它应该适合你。
答案 2 :(得分:0)
public class MainActivity extends Activity {
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(com.example.lines.R.layout.activity_main);
Paint paint = new Paint();
paint.setColor(Color.RED);
paint.setStyle(Paint.Style.STROKE);
paint.setStrokeWidth(3);
Bitmap bg = Bitmap.createBitmap(480,800, Bitmap.Config.ARGB_8888);
Canvas can = new Canvas(bg);
int left1 = 10;
int top1 = 10;
int right1 = 30;
int bottom1 = 30;
for(int j=0; j< 31; j++)
{
for(int i=0; i<23;i++)
{
RectF rectF1 = new RectF(left1,top1,right1,bottom1);
can.drawArc(rectF1, 0, 180, false, paint);
left1 = right1;
right1 = left1+20;
}
System.out.println("\n");
left1 = 10;
top1 = bottom1 + 1;
right1 = 30;
bottom1 = 30+top1 - 6;
}
LinearLayout l1 = (LinearLayout)findViewById(com.example.lines.R.id.drawarea);
l1.setBackgroundDrawable(new BitmapDrawable(bg));
}