我正在尝试只获取包含text,ex xml:
的元素<root>
<Item>
<ItemID>4504216603</ItemID>
<ListingDetails>
<StartTime>10:00:10.000Z</StartTime>
<EndTime>10:00:30.000Z</EndTime>
<ViewItemURL>http://url</ViewItemURL>
....
</item>
应打印
Element Local Name:ItemID
Text:4504216603
Element Local Name:StartTime
Text:10:00:10.000Z
Element Local Name:EndTime
Text:10:00:30.000Z
Element Local Name:ViewItemURL
Text:http://url
此代码还打印root,item等。它是否可能,它一定是我不能谷歌它。
XMLInputFactory inputFactory = XMLInputFactory.newInstance();
InputStream input = new FileInputStream(new File("src/main/resources/file.xml"));
XMLStreamReader xmlStreamReader = inputFactory.createXMLStreamReader(input);
while (xmlStreamReader.hasNext()) {
int event = xmlStreamReader.next();
if (event == XMLStreamConstants.START_ELEMENT) {
System.out.println("Element Local Name:" + xmlStreamReader.getLocalName());
}
if (event == XMLStreamConstants.CHARACTERS) {
if(!xmlStreamReader.getText().trim().equals("")){
System.out.println("Text:"+xmlStreamReader.getText().trim());
}
}
}
编辑错误行为:
Element Local Name:root
Element Local Name:item
Element Local Name:ItemID
Text:4504216603
Element Local Name:ListingDetails
Element Local Name:StartTime
Text:10:00:10.000Z
Element Local Name:EndTime
Text:10:00:30.000Z
Element Local Name:ViewItemURL
Text:http://url
我不希望打印根和其他没有文本的节点,只是我上面写的输出。谢谢
答案 0 :(得分:2)
试试这个:
while (xmlStreamReader.hasNext()) {
int event = xmlStreamReader.next();
if (event == XMLStreamConstants.START_ELEMENT) {
try {
String text = xmlStreamReader.getElementText();
System.out.println("Element Local Name:" + xmlStreamReader.getLocalName());
System.out.println("Text:" + text);
} catch (XMLStreamException e) {
}
}
}
基于SAX的解决方案(有效):
public class Test extends DefaultHandler {
public static void main(String[] args) throws ParserConfigurationException, IOException, SAXException, XPathExpressionException, XMLStreamException {
SAXParser parser = SAXParserFactory.newInstance().newSAXParser();
parser.parse(new File("src/file.xml"), new Test());
}
private String currentName;
@Override
public void startElement(String uri, String localName, String qName, Attributes attributes) throws SAXException {
currentName = qName;
}
@Override
public void characters(char[] ch, int start, int length) throws SAXException {
String string = new String(ch, start, length);
if (hasText(string)) {
System.out.println(currentName);
System.out.println(string);
}
}
private boolean hasText(String string) {
string = string.trim();
return string.length() > 0;
}
}
答案 1 :(得分:0)
Stax解决方案:
解析文件
public void parseXML(InputStream xml) {
try {
DOMResult result = new DOMResult();
XMLInputFactory xmlInputFactory = XMLInputFactory.newInstance();
XMLEventReader reader = xmlInputFactory.createXMLEventReader(new StreamSource(xml));
TransformerFactory transFactory = TransformerFactory.newInstance();
Transformer transformer = transFactory.newTransformer();
transformer.transform(new StAXSource(reader), result);
Document document = (Document) result.getNode();
NodeList startlist = document.getChildNodes();
processNodeList(startlist);
} catch (Exception e) {
System.err.println("Something went wrong, this might help :\n" + e.getMessage());
}
}
现在文档中的所有节点都在NodeList中,所以接下来要做这个:
private void processNodeList(NodeList nodelist) {
for (int i = 0; i < nodelist.getLength(); i++) {
if (nodelist.item(i).getNodeType() == Node.ELEMENT_NODE && (hasValidAttributes(nodelist.item(i)) || hasValidText(nodelist.item(i)))) {
getNodeNamesAndValues(nodelist.item(i));
}
processNodeList(nodelist.item(i).getChildNodes());
}
}
然后为每个具有有效文本的元素节点获取名称和值
public void getNodeNamesAndValues(Node n) {
String nodeValue = null;
String nodeName = null;
if (hasValidText(n)) {
while (n != null && isWhiteSpace(n.getTextContent()) == true && StringUtils.isWhitespace(n.getTextContent()) && n.getNodeType() != Node.ELEMENT_NODE) {
n = n.getFirstChild();
}
nodeValue = StringUtils.strip(n.getTextContent());
nodeName = n.getLocalName();
System.out.println(nodeName + " " + nodeValue);
}
}
检查节点的一些有用方法:
private static boolean hasValidAttributes(Node node) {
return (node.getAttributes().getLength() > 0);
}
private boolean hasValidText(Node node) {
String textValue = node.getTextContent();
return (textValue != null && textValue != "" && isWhiteSpace(textValue) == false && !StringUtils.isWhitespace(textValue) && node.hasChildNodes());
}
private boolean isWhiteSpace(String nodeText) {
if (nodeText.startsWith("\r") || nodeText.startsWith("\t") || nodeText.startsWith("\n") || nodeText.startsWith(" "))
return true;
else
return false;
}
我也使用了StringUtils,你可以通过在你的pom.xml中包含它来获得它,如果你正在使用maven:
<dependency>
<groupId>commons-lang</groupId>
<artifactId>commons-lang</artifactId>
<version>2.5</version>
</dependency>
如果您正在阅读大文件,这是低效的,但如果您先拆分它们则不是那么多。这就是我带来的(谷歌)。有更好的解决方案,这是我的,我是业余的(现在)。