Question

我尝试在swift 2.0中提出一些网址请求：

func chackAccess(username: String!, password: String!) {
    let request = NSMutableURLRequest(URL: NSURL(string: url)!)
    request.HTTPMethod = "POST"
    let postString = "username=\(username)&password=\(password)"

    request.HTTPBody = postString.dataUsingEncoding(NSUTF8StringEncoding)


    let task = NSURLSession.sharedSession().dataTaskWithRequest(request) {
        data, response, error in

        if error != nil {
            print("error=\(error)")
            return
        }

        let responseString = NSString(data: data!, encoding: NSUTF8StringEncoding)
        print("responseString = \(responseString!)")

        if responseString != "null" {

            dispatch_async(dispatch_get_main_queue(), { () -> Void in
                self.performSegueWithIdentifier("login", sender: self)
            })
        } else {
            print("shake")
            dispatch_async(dispatch_get_main_queue(), { () -> Void in
                self.wrongPassword()
            })
        }
    }
    task.resume()

}

只有当我拥有像a-z 0-9这样的简单密码时，一切都很有效（但问题是char +。

问题出在哪里？

Answer 1

某些字符在网址字符串中具有特殊含义：&分隔参数，+代表空格等。

尝试逃避它的百分比：

let charset = NSMutableCharacterSet.alphanumericCharacterSet()
let username = "auser"
let password = "abc(+.,?/[])123".stringByAddingPercentEncodingWithAllowedCharacters(charset)!

let postString = "username=\(username)&password=\(password)"
// username=auser&password=abc%28%2B%2E%2C%3F%2F%5B%5D%29123

stringByAddingPercentEncodingWithAllowedCharacters(charset)转义不在charset中的所有字符。例如：+ --> %2B

带有“+”等特殊字符的NSUTF8StringEncoding问题

1 个答案: