Question

public class BinaryToDecimal{
public static void main(String[]args){
    int binary = 101011101;
    int d = 10;
    int l = 1;
    for (int j=1;j<=8;j++){
        int r = (binary/d%10)*l;
        int k = r;
        int z = r + k;
        d*=10;
        l*=2;
    }
    System.out.println("The binary number " + binary + " is equivalent to "+ z +" in decimal."); // z here is out of scope of for
}

}

我只需要使用for循环完成这项任务，但我找不到工作代码......这是我做的最好的。

Answer 1

这是一个使用2^x逻辑的非常简单的算法。

它基本上做的是：

如果我们在二进制变量中遇到1，我们会将2^(Position of the 1)添加到decimal变量

class MyClass{

    public static void main(String[] args) {
        int bin = 101;
        String binary = String.valueOf(bin);
        int decimal = 0;

        for (int i = 0 ; i < binary.length() ; i++){
            if (binary.charAt(i) == '1'){
                decimal += Math.pow(2, binary.length() - i - 1);
            }
        }

        System.out.println(decimal);
    }
}

Answer 2

public class BinaryToDecimal{
public static void main(String[]args){
    int binary = 101011101;
    int powerOfTen = 10;
    int powerOfTwo = 1;
    int Decimal = 0;
    for (int j=1;j<=8;j++){
        int splitAnswer = (binary/powerOfTen%10)*powerOfTwo;
        int old = splitAnswer;
        Decimal = splitAnswer + old;
        powerOfTen*=10;
        powerOfTwo*=2;
    }
    System.out.println("The binary number " + binary + " is equivalent to "+ Decimal +" in decimal.");
}

}

无法找到解决方案

2 个答案: