Question

如何检测字符串是否包含某个单词？例如，我有一个字符串，其下面是：

@"Here is my string."

我想知道我是否可以检测字符串中的单词，例如“是”。

Answer 1

我将如何做到这一点：

NSString *someString = @"Here is my string";
NSRange isRange = [someString rangeOfString:@"is " options:NSCaseInsensitiveSearch];
if(isRange.location == 0) {
   //found it...
} else {
   NSRange isSpacedRange = [someString rangeOfString:@" is " options:NSCaseInsensitiveSearch];
   if(isSpacedRange.location != NSNotFound) {
      //found it...
   }
}

您可以轻松地将其作为类别添加到NSString：

@interface NSString (JRStringAdditions) 

- (BOOL)containsString:(NSString *)string;
- (BOOL)containsString:(NSString *)string
               options:(NSStringCompareOptions)options;

@end

@implementation NSString (JRStringAdditions) 

- (BOOL)containsString:(NSString *)string
               options:(NSStringCompareOptions)options {
   NSRange rng = [self rangeOfString:string options:options];
   return rng.location != NSNotFound;
}

- (BOOL)containsString:(NSString *)string {
   return [self containsString:string options:0];
}

@end

Answer 2

使用以下代码扫描句子中的单词。

NSString *sentence = @"The quick brown fox";
NSString *word = @"quack";
if ([sentence rangeOfString:word].location != NSNotFound) {
    NSLog(@"Yes it does contain that word");
}

Answer 3

在iOS8中，您现在可以使用：

BOOL containsString = [@"Here is my string." containsString:@"is"];

关于如何改造＆＃34;这是一篇有趣的帖子。它到iOS7这里： http://petersteinberger.com/blog/2014/retrofitting-containsstring-on-ios-7/

Answer 4

我建议使用NSLinguisticTagger。我们可以使用它来搜索Here is my string. His isn't a mississippi isthmus. It is?

NSLinguisticTagger *linguisticTagger = [[NSLinguisticTagger alloc] initWithTagSchemes:@[
                                        NSLinguisticTagSchemeTokenType,
                                        ]
                                                                              options:
                                        NSLinguisticTaggerOmitPunctuation |
                                        NSLinguisticTaggerOmitWhitespace |
                                        NSLinguisticTaggerOmitOther ];
[linguisticTagger setString:@"Here is my string. His isn't a mississippi isthmus. It is?"];
[linguisticTagger enumerateTagsInRange:NSMakeRange(0,
                                                   [[linguisticTagger string] length])
                                scheme:NSLinguisticTagSchemeTokenType
                               options:
 NSLinguisticTaggerOmitPunctuation |
 NSLinguisticTaggerOmitWhitespace |
 NSLinguisticTaggerOmitOther |
 NSLinguisticTaggerJoinNames
                            usingBlock:^(NSString *tag, NSRange tokenRange, NSRange sentenceRange, BOOL *stop) {
                                NSLog(@"tag: %@, tokenRange: %@, sentenceRange: %@, token: %@",
                                      tag,
                                      NSStringFromRange(tokenRange),
                                      NSStringFromRange(sentenceRange),
                                      [[linguisticTagger string] substringWithRange:tokenRange]);
                            }];

输出：

tag: Word, tokenRange: {0, 4}, sentenceRange: {0, 19}, token: Here
tag: Word, tokenRange: {5, 2}, sentenceRange: {0, 19}, token: is
tag: Word, tokenRange: {8, 2}, sentenceRange: {0, 19}, token: my
tag: Word, tokenRange: {11, 6}, sentenceRange: {0, 19}, token: string
tag: Word, tokenRange: {19, 3}, sentenceRange: {19, 33}, token: His
tag: Word, tokenRange: {23, 2}, sentenceRange: {19, 33}, token: is
tag: Word, tokenRange: {25, 3}, sentenceRange: {19, 33}, token: n't
tag: Word, tokenRange: {29, 1}, sentenceRange: {19, 33}, token: a
tag: Word, tokenRange: {31, 11}, sentenceRange: {19, 33}, token: mississippi
tag: Word, tokenRange: {43, 7}, sentenceRange: {19, 33}, token: isthmus
tag: Word, tokenRange: {52, 2}, sentenceRange: {52, 6}, token: It
tag: Word, tokenRange: {55, 2}, sentenceRange: {52, 6}, token: is

它会忽略His mississippi和isthmus，甚至会识别is内的isn't。

Answer 5

我希望这可以帮助你，..在.m文件中添加此行或创建一个单独的类并集成此代码。

@implementation NSString (Contains)

- (BOOL) containsString: (NSString*) substring
{
NSRange range = [self rangeOfString : substring];
BOOL found = ( range.location != NSNotFound );
return found;
}    
@end

Answer 6

使用iOS 8和Swift，我们可以使用localizedCaseInsensitiveContainsString方法

 let string: NSString = "Café"
 let substring: NSString = "É"

 string.localizedCaseInsensitiveContainsString(substring) // true

Answer 7

完整的解决方案首先扫描字符串（不添加空格），然后检查前一个字符是空白还是行首。同样，检查紧随其后的字符是空白还是行尾。如果两个测试都通过，那么你就匹配了。根据您的需要，您还可以检查,，.，()等。

当然，另一种方法是将字符串解析为单词并单独检查每个单词。

检测NSString是否包含......？

7 个答案: