Question

我有这样的XML：

    <video id="647599250">
        <studio/>
        <director/>
        <actorRef>916503210</actorRef>
        <title>National Geographic's Mysteries of Egypt</title>
        <dvd>22</dvd>
        <laserdisk/>
        <laserdisk_stock/>
        <genre>special</genre>
        <rating>R</rating>
        <runtime>110</runtime>
        <user_rating>3</user_rating>
        <summary>Experience the magnificence of Egypt like never before!</summary>
        <details>Legendary actor and native Egyptian Omar Sharif and Kate Maberly join National Geographic's award-winning filmmakers to weave a fascinating story of a grandfather who enchants his granddaughter with tales of tombs and treasures. Travel back more than 4,000 years to a time when the Great Pyramids of Giza were built.</details>
        <vhs>15</vhs>
        <beta_stock>5</beta_stock>
        <year>1999</year>
        <vhs_stock>88</vhs_stock>
        <dvd_stock>22</dvd_stock>
        <beta>14</beta>
    </video>

有很多电影标签。

我正在运行以下代码：

for $movie in result/videos//video
order by $movie/genre, $movie/user_rating descending
return $movie/title

产生：

<?xml version="1.0" encoding="UTF-8"?>
<title>Enemy of the State</title>
<title>Star Wars</title>
<title>The Fugitive</title>
<title>Clerks</title>
<title>Six Days Seven Nights</title>
<title>Doquissåpan, avsnitt 1</title>
<title>Doquissåpan, avsnitt 2</title>
<title>Doquissåpan, avsnitt 4</title>
<title>Contact</title>
<title>2001: A Space Odyssey</title>
<title>Pinocchio</title>
<title>MUPPET TREASURE ISLAND</title>
<title>Au Revoir Les Enfants</title>
<title>La Femme Nikita</title>
<title>Seven</title>
<title>The Fear</title>
<title>Yellow Submarine</title>
<title>Carmen</title>
<title>Everest</title>
<title>National Geographic's Mysteries of Egypt</title>

此序列已按流派排序，然后通过user_rating在流派内排序。我想知道是否还有为每个类型的电影创建某种标题，如：

<genre genre="action">
<title>Enemy of the State</title>
<title>Star Wars</title >
<title>The Fugitive</title>
</genre > 
<genre genre="comedy">
<title>Clerks</title>
<title>Six Days Seven Nights</title>
</genre> 
<genre genre="drama">
<title>Contact</title>
<title>2001: A Space Odyssey</title>
</genre> 
<genre genre="family">
<title>Pinocchio</title>
<title>MUPPET TREASURE ISLAND</title>
</genre>
<genre genre="foreign">
<title>Au Revoir Les Enfants</title>
<title>La Femme Nikita</title>
</genre> 
<genre genre="horror">
<title>Seven</title>
<title>The Fear</title>
</genre> 
<genre genre="musical">
<title>Yellow Submarine</title>
<title>Carmen</title>
</genre> 
<genre genre="special">
<title>Everest</title>
<title>National Geographic’s Mysteries of Egypt</title>
</genre>
<genre genre="documentary">
<title>Doquissåpan, avsnitt 1</title> 
<title>Doquissåpan, avsnitt 2</title> 
<title>Doquissåpan, avsnitt 4</title>
</genre>

Answer 1

试试这个：

for $genre in distinct-values(result/videos/video/genre)
order by $genre
return 
    <genre genre="{ data($genre) }">
    {
        for $movie in result/videos/video[genre=$genre]            
        order by $movie/user_rating
        return $movie/title
    }
    </genre>

此外，它可以写成：

@RequestMapping(value = "/searchmedia", method = RequestMethod.GET)
public String searchForm(HttpServletRequest request, Map<String, Object> map) {

    // This is what I want to get to the JSP file
    Iterable<MediaFile> mediaFiles = repository.findAll();

    map.put("mediaFiles", mediaFiles);

    return "search";
}

XML：组

1 个答案: