脚本不会从CSV文件转到URL',我做错了什么?脚本没有任何错误。
var macro;
macro = "CODE:";
macro += "SET !EXTRACT_TEST_POPUP NO" + "\n";
macro += "SET !DATASOURCE Facebook_Groups.csv" + "\n";
macro += "SET !DATASOURCE_COLUMNS 1000" + "\n";
macro += "SET !LOOP 1" + "\n";
macro += "SET !DATASOURCE_LINE {{!LOOP}}" + "\n";
macro += "URL GOTO='{{!COL1}}'" + "\n";
macro += "TAG POS=1 TYPE=I ATTR=CLASS:'img sp_sn-egcmZHgp sx_3e65cc'" + "\n";
答案 0 :(得分:1)
var macro;
macro = "CODE:";
macro += "SET !EXTRACT_TEST_POPUP NO" + "\n";
macro += "SET !DATASOURCE Facebook_Groups.csv" + "\n";
macro += "SET !DATASOURCE_COLUMNS 1000" + "\n";
macro += "SET !LOOP 1" + "\n";
macro += "SET !DATASOURCE_LINE {{!LOOP}}" + "\n";
macro += "URL GOTO='{{!COL1}}'" + "\n";
macro += "TAG POS=1 TYPE=I ATTR=CLASS:img<sp>sp_sn-egcmZHgp<sp>sx_3e65cc" + "\n";
iimPlay(macro)