如何在保留字符串/ int键的同时合并两个数组(一个使用string =>值对,另一个使用int =>值对)?它们都不会重叠(因为一个只有字符串而另一个只有整数)。
这是我当前的代码(不起作用,因为array_merge使用整数键重新索引数组):
// get all id vars by combining the static and dynamic
$staticIdentifications = array(
Users::userID => "USERID",
Users::username => "USERNAME"
);
// get the dynamic vars, formatted: varID => varName
$companyVarIdentifications = CompanyVars::getIdentificationVarsFriendly($_SESSION['companyID']);
// merge the static and dynamic vars (*** BUT KEEP THE INT INDICES ***)
$idVars = array_merge($staticIdentifications, $companyVarIdentifications);
答案 0 :(得分:506)
您可以简单地“添加”数组:
>> $a = array(1, 2, 3);
array (
0 => 1,
1 => 2,
2 => 3,
)
>> $b = array("a" => 1, "b" => 2, "c" => 3)
array (
'a' => 1,
'b' => 2,
'c' => 3,
)
>> $a + $b
array (
0 => 1,
1 => 2,
2 => 3,
'a' => 1,
'b' => 2,
'c' => 3,
)
答案 1 :(得分:51)
考虑到你有
$replaced = array('1' => 'value1', '4' => 'value4');
$replacement = array('4' => 'value2', '6' => 'value3');
执行$merge = $replacement + $replaced;
将输出:
Array('1' => 'value1', '4' => 'value2', '6' => 'value3');
sum中的第一个数组将在最终输出中包含值。
执行$merge = $replaced + $replacement;
将输出:
Array('1' => 'value1', '4' => 'value4', '6' => 'value3');
答案 2 :(得分:15)
虽然这个问题很老,但我只是希望在保留密钥的同时增加另一种合并的可能性。
除了使用+
符号向现有数组添加键/值之外,您还可以执行array_replace
。
$a = array('foo' => 'bar', 'some' => 'string');
$b = array(42 => 'answer to the life and everything', 1337 => 'leet');
$merged = array_replace($a, $b);
相同的键将被后一个数组覆盖
还有一个array_replace_recursive
,它也用于子阵列。
答案 3 :(得分:1)
可以很容易地添加或合并两个数组,而无需更改 + 运算符的原始索引。这对于laravel和codeigniter select下拉列表将非常有帮助。
$empty_option = array(
''=>'Select Option'
);
$option_list = array(
1=>'Red',
2=>'White',
3=>'Green',
);
$arr_option = $empty_option + $option_list;
输出将是:
$arr_option = array(
''=>'Select Option'
1=>'Red',
2=>'White',
3=>'Green',
);
答案 4 :(得分:0)
尝试使用array_replace_recursive或array_replace函数
$a = array('userID' => 1, 'username'=> 2);
array (
userID => 1,
username => 2
)
$b = array('userID' => 1, 'companyID' => 3);
array (
'userID' => 1,
'companyID' => 3
)
$c = array_replace_recursive($a,$b);
array (
userID => 1,
username => 2,
companyID => 3
)
http://php.net/manual/en/function.array-replace-recursive.php
答案 5 :(得分:0)
你好 2010 年的问题。
OP. 的要求是保留密钥(保留密钥)而不是重叠(我认为覆盖)。在某些情况下,例如数字键,这是可能的,但如果是字符串键,则似乎不可能。
如果您使用 array_merge()
,数字键将始终重新索引或重新编号。
如果您使用 array_replace()
, array_replace_recursive()
它将从右到左重叠或覆盖。第一个数组中具有相同键的值将替换为第二个数组。
如果您使用 $array1 + $array2
作为提到的注释,如果键相同,那么它将保留第一个数组中的值,但删除第二个数组。
这是我刚刚编写的用于处理相同需求的函数。您可以免费用于任何目的。
/**
* Array custom merge. Preserve indexed array key (numbers) but overwrite string key (same as PHP's `array_merge()` function).
*
* If the another array key is string, it will be overwrite the first array.<br>
* If the another array key is integer, it will be add to first array depend on duplicated key or not.
* If it is not duplicate key with the first, the key will be preserve and add to the first array.
* If it is duplicated then it will be re-index the number append to the first array.
*
* @param array $array1 The first array is main array.
* @param array ...$arrays The another arrays to merge with the first.
* @return array Return merged array.
*/
function arrayCustomMerge(array $array1, array ...$arrays): array
{
foreach ($arrays as $additionalArray) {
foreach ($additionalArray as $key => $item) {
if (is_string($key)) {
// if associative array.
// item on the right will always overwrite on the left.
$array1[$key] = $item;
} elseif (is_int($key) && !array_key_exists($key, $array1)) {
// if key is number. this should be indexed array.
// and if array 1 is not already has this key.
// add this array with the key preserved to array 1.
$array1[$key] = $item;
} else {
// if anything else...
// get all keys from array 1 (numbers only).
$array1Keys = array_filter(array_keys($array1), 'is_int');
// next key index = get max array key number + 1.
$nextKeyIndex = (intval(max($array1Keys)) + 1);
unset($array1Keys);
// set array with the next key index.
$array1[$nextKeyIndex] = $item;
unset($nextKeyIndex);
}
}// endforeach; $additionalArray
unset($item, $key);
}// endforeach;
unset($additionalArray);
return $array1;
}// arrayCustomMerge
<?php
$array1 = [
'cat',
'bear',
'fruitred' => 'apple',
3.1 => 'dog',
null => 'null',
];
$array2 = [
1 => 'polar bear',
20 => 'monkey',
'fruitred' => 'strawberry',
'fruityellow' => 'banana',
null => 'another null',
];
// require `arrayCustomMerge()` function here.
function printDebug($message)
{
echo '<pre>';
print_r($message);
echo '</pre>' . PHP_EOL;
}
echo 'array1: <br>';
printDebug($array1);
echo 'array2: <br>';
printDebug($array2);
echo PHP_EOL . '<hr>' . PHP_EOL . PHP_EOL;
echo 'arrayCustomMerge:<br>';
$merged = arrayCustomMerge($array1, $array2);
printDebug($merged);
assert($merged[0] == 'cat', 'array key 0 should be \'cat\'');
assert($merged[1] == 'bear', 'array key 1 should be \'bear\'');
assert($merged['fruitred'] == 'strawberry', 'array key \'fruitred\' should be \'strawberry\'');
assert($merged[3] == 'dog', 'array key 3 should be \'dog\'');
assert(array_search('another null', $merged) !== false, '\'another null\' should be merged.');
assert(array_search('polar bear', $merged) !== false, '\'polar bear\' should be merged.');
assert($merged[20] == 'monkey', 'array key 20 should be \'monkey\'');
assert($merged['fruityellow'] == 'banana', 'array key \'fruityellow\' should be \'banana\'');
结果。
array1:
Array
(
[0] => cat
[1] => bear
[fruitred] => apple
[3] => dog
[] => null
)
array2:
Array
(
[1] => polar bear
[20] => monkey
[fruitred] => strawberry
[fruityellow] => banana
[] => another null
)
---
arrayCustomMerge:
Array
(
[0] => cat
[1] => bear
[fruitred] => strawberry
[3] => dog
[] => another null
[4] => polar bear
[20] => monkey
[fruityellow] => banana
)