我遇到了一个非常简单的问题。我有登录表单,用户名,密码和按钮。在我的按钮处理程序中,我尝试获取textinput值。但总是得到不确定的价值。我错过了什么吗?
render() {
<ExScreen
headerColor={this.state.headerColor}
scrollEnabled={this.state.enableScroll}
style={styles.container} >
<View >
<View >
<View style={[styles.inputContainer]} >
<TextInput
ref= "username"
onChangeText={(text) => this.setState({text})}
value={this.state.username}
/>
</View>
<Button style={{color: 'white', marginTop: 30, borderWidth: 1, borderColor: 'white', marginLeft: 20*vw, marginRight: 20*vw, height: 40, padding: 10}}
onPress={this._handlePress.bind(this)}>
Sign In
</Button>
...
_handlePress(event) {
var username=this.refs.username.value;
答案 0 :(得分:46)
快速且不太优化的方法是在onChangeText回调中使用arrow函数,方法是将username
作为参数传递给onChangeText回调。
<TextInput
ref= {(el) => { this.username = el; }}
onChangeText={(username) => this.setState({username})}
value={this.state.username}
/>
然后在您的_handlePress
方法
_handlePress(event) {
let username=this.state.username;
}
但这有几个缺点!!!
最佳做法是使用像handleInputChange
这样的处理程序,并在构造函数中绑定```this``。
...
constructor(props) {
super(props);
this.handleInputChange = this.handleInputChange.bind(this);
}
...
handleInputChange(event = {}) {
const name = event.target && event.target.name;
const value = event.target && event.target.value;
this.setState([name]: value);
}
...
render() {
...
<TextInput
name="username"
onChangeText={this.handleChange}
value={this.state.username}
/>
...
}
...
或者,如果您使用es6类属性速记,它会自动绑定this
。但是在测试和性能方面,这有缺点。 Read More Here
...
handleInputChange = (event = {}) => {
const name = event.target && event.target.name;
const value = event.target && event.target.value;
this.setState([name]: value);
}
...
render() {
...
<TextInput
name="username"
onChangeText={this.handleChange}
value={this.state.username}
/>
...
}
...
答案 1 :(得分:16)
在React Native 0.43中:(可能晚于0.43就可以了。)
---
version_001:
id: 1
item_type: 'DistributionChannel'
item_id: 1
event: 'create'
whodunnit: <%= User.find_by(email: 'user@example.com').id.to_s %>
object: nil
created_at: 2017-05-15 12:00:00.000000000 Z
object_changes: '---\\nid:\\n- \\n- 1\\nprimary_channel:\\n- \\n- Best Buy\\nsecondary_channel:\\n- \\n- ''\ncreated_at:\\n- \\n- 2017-05-15 12:00:00.000000000 Z\\nupdated_at:\\n- \\n- 2017-05-15 12:00:00.000000000 Z\\n'
答案 2 :(得分:13)
如果您像我一样,并且不想使用或污染一次性组件的状态,这就是我所做的:
export default class Registartion extends Component {
_register = () => {
const payload = {
firstName: this.firstName,
/* other values */
}
console.log(payload)
}
render() {
return (
<RegisterLayout>
<Text style={styles.welcome}>
Register
</Text>
<InputText
placeholder="First Name"
onChangeText={(text) => this.firstName = text} />
// More components...
<CustomButton
backgroundColor="steelblue"
handlePress={this._register}>
Submit
</CustomButton>
</RegisterLayout>
)
}
}
答案 3 :(得分:8)
您应该使用状态来存储输入字段的值。 https://facebook.github.io/react-native/docs/state.html
setState
onChangeText = {(value)=&gt; this.setState({username:value})}
this.state.username
示例代码
export default class Login extends Component {
state = {
username: 'demo',
password: 'demo'
};
<Text style={Style.label}>User Name</Text>
<TextInput
style={Style.input}
placeholder="UserName"
onChangeText={(value) => this.setState({username: value})}
value={this.state.username}
/>
<Text style={Style.label}>Password</Text>
<TextInput
style={Style.input}
placeholder="Password"
onChangeText={(value) => this.setState({password: value})}
value={this.state.password}
/>
<Button
title="LOGIN"
onPress={() =>
{
if(this.state.username.localeCompare('demo')!=0){
ToastAndroid.show('Invalid UserName',ToastAndroid.SHORT);
return;
}
if(this.state.password.localeCompare('demo')!=0){
ToastAndroid.show('Invalid Password',ToastAndroid.SHORT);
return;
}
//Handle LOGIN
}
}
/>
答案 4 :(得分:4)
请注意如何使用setState()。正确的形式是
this.setState({
Key: Value,
});
所以我会这样做:
onChangeText={(event) => this.setState({username:event.nativeEvent.text})}
...
var username=this.state.username;
答案 5 :(得分:2)
export default class App extends Component {
state = { username: '', password: '' }
onChangeText = (key, val) => {
this.setState({ [key]: val})
}
render() {
return (
<View style={styles.container}>
<Text>Login Form</Text>
<TextInput
placeholder='Username'
onChangeText={val => this.onChangeText('username', val)}
style={styles.input}
/>
<TextInput
placeholder='Password'
onChangeText={val => this.onChangeText('password', val)}
style={styles.input}
secureTextEntry={true}
/>
</View>
);
}
}
希望这可以解决您的问题
答案 6 :(得分:2)
只需这样做。
this.state={f_name:""};
textChangeHandler = async (key, val) => {
await this.setState({ [key]: val });
}
<Textfield onChangeText={val => this.textChangeHandler('f_name', val)}>
答案 7 :(得分:1)
这对我有用
<Form>
<TextInput
style={{height: 40}}
placeholder="userName"
onChangeText={(text) => this.userName = text}
/>
<TextInput
style={{height: 40}}
placeholder="Password"
onChangeText={(text) => this.Password = text}
/>
<Button
title="Sign in!"
onPress={this._signInAsync}
/>
</Form>
和
_signInAsync = async () => {
console.log(this.userName)
console.log(this.Password)
};
答案 8 :(得分:1)
尝试控制台记录对象,您将在nativeEvent.text中找到输入的文本
示例:
handelOnChange = (enteredText) => {
console.log(enteredText.nativeEvent.text)
}
render()
return (
<SafeAreaView>
<TextInput
onChange={this.handelOnChange}
>
</SafeAreaView>
)
答案 9 :(得分:0)
班级初级用户:
constructor() {
super()
this.state = {
email: ''
}
}
然后在某个功能中:
handleSome = () => {
console.log(this.state.email)
};
在输入中:
<TextInput onChangeText={(email) => this.setState({email})}/>
答案 10 :(得分:0)
如果设置文本状态,为什么不直接使用它?
_handlePress(event) {
var username=this.state.text;
当然,变量命名可能比“文本”更具描述性,但是你的调用。
答案 11 :(得分:0)
通过此过程,一切对我都可以:
<Input onChangeText={this.inputOnChangeText} />
还有:
inputOnChangeText = (e) => {
this.setState({
username: e
})
}
答案 12 :(得分:0)
constructor(props) {
super(props);
this.state ={
commentMsg: ''
}
}
onPress = () => {
alert("Hi " +this.state.commentMsg)
}
<View style={styles.sendCommentContainer}>
<TextInput
style={styles.textInput}
multiline={true}
onChangeText={(text) => this.setState({commentMsg: text})}
placeholder ='Comment'/>
<Button onPress={this.onPress}
title="OK!"
color="#841584"
/>
</TouchableOpacity>
</View>
答案 13 :(得分:0)
onChange
的{{1}}和onTextChange
道具之间存在巨大差异。不要像我一样使用<TextInput />
返回onTextChange
,不要使用string
返回完整对象。
花1个小时弄清楚自己的价值在哪里,我感到很愚蠢。
答案 14 :(得分:-1)
这段代码对我有用。我错过的是我没有在按钮动作中传递'this':
onPress={this._handlePress.bind(this)}>
--------------
_handlePress(event) {
console.log('Pressed!');
var username = this.state.username;
var password = this.state.password;
console.log(username);
console.log(password);
}
render() {
return (
<View style={styles.container}>
<TextInput
ref="usr"
style={{height: 40, borderColor: 'gray', borderWidth: 1 , marginTop: 10 , padding : 10 , marginLeft : 5 , marginRight : 5 }}
placeHolder= "Enter username "
placeholderTextColor = '#a52a2a'
returnKeyType = {"next"}
autoFocus = {true}
autoCapitalize = "none"
autoCorrect = {false}
clearButtonMode = 'while-editing'
onChangeText={(text) => {
this.setState({username:text});
}}
onSubmitEditing={(event) => {
this.refs.psw.focus();
}}
/>
<TextInput
ref="psw"
style={{height: 40, borderColor: 'gray', borderWidth: 1 , marginTop: 10,marginLeft : 5 , marginRight : 5}}
placeholder= "Enter password"
placeholderTextColor = '#a52a2a'
autoCapitalize = "none"
autoCorrect = {false}
returnKeyType = {'done'}
secureTextEntry = {true}
clearButtonMode = 'while-editing'
onChangeText={(text) => {
this.setState({password:text});
}}
/>
<Button
style={{borderWidth: 1, borderColor: 'blue'}}
onPress={this._handlePress.bind(this)}>
Login
</Button>
</View>
);``
}
}
答案 15 :(得分:-2)
你试过吗
var username=this.state.username;