Question

我编写了一个包含两个实体的小型SpringBoot应用程序。它们如下所示，与电话具有OneToMany关系的人：

  import java.util.HashSet;
import java.util.Set;

import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.GeneratedValue;
import javax.persistence.GenerationType;
import javax.persistence.Id;
import javax.persistence.OneToMany;

@Entity

public class Person {

    @OneToMany(mappedBy="person")
    private Set<Phone> phones = new HashSet<>();

    @Id
    @GeneratedValue(strategy = GenerationType.AUTO) 
    private long id;

    private String firstName;
    private String lastName;

    @Column(columnDefinition="int default 0")
    private Integer age;



    public Person() {
        super();
    }

    public Person(String firstName, String lastName, Integer age) {

        this.firstName = firstName;
        this.lastName = lastName;
        this.age = age;
    }

    public long getId() {
        return id;
    }

    public Set<Phone> getPhones() {
        return phones;
    }

    public void setPhones(Set<Phone> phones) {
        this.phones = phones;
    }

    public String getFirstName() {
        return firstName;
    }

    public void setFirstName(String firstName) {
        this.firstName = firstName;
    }

    public String getLastName() {
        return lastName;
    }

    public void setLastName(String lastName) {
        this.lastName = lastName;
    }

    public Integer getAge() {
        return age;
    }

    public void setAge(Integer age) {
        this.age = age;
    }



}

Phone实体有ManyToOne：

package org.prdas;

import javax.persistence.Entity;
import javax.persistence.GeneratedValue;
import javax.persistence.GenerationType;
import javax.persistence.Id;
import javax.persistence.ManyToOne;

@Entity
public class Phone {

    @ManyToOne
    private Person person;

    @Id
    @GeneratedValue(strategy = GenerationType.AUTO) 
    private Long id;

    private String homePhone;
    private String workPhone;

    public Phone() {

    }

    public Phone(Person person, String homePhone, String workPhone) {

        this.person = person;
        this.homePhone = homePhone;
        this.workPhone = workPhone;
    }

    public Person getPerson() {
        return person;
    }

    public void setPerson(Person person) {
        this.person = person;
    }

    public String getHomePhone() {
        return homePhone;
    }

    public void setHomePhone(String homePhone) {
        this.homePhone = homePhone;
    }

    public String getWorkPhone() {
        return workPhone;
    }

    public void setWorkPhone(String workPhone) {
        this.workPhone = workPhone;
    }

    public Long getId() {
        return id;
    }   

}

我已经定义了以下两个存储库：

import java.util.List;

import org.springframework.data.repository.PagingAndSortingRepository;
import org.springframework.data.repository.query.Param;
import org.springframework.data.rest.core.annotation.RepositoryRestResource;

@RepositoryRestResource(collectionResourceRel = "people", path = "people")
public interface PersonRepository extends PagingAndSortingRepository<Person, Long> {

    List<Person> findByLastName(@Param("name") String name);
    List<Person> findByFirstName(@Param("name") String name);

}


import java.util.Collection;

import org.springframework.data.jpa.repository.JpaRepository;
import org.springframework.data.repository.query.Param;
import org.springframework.data.rest.core.annotation.RepositoryRestResource;

@RepositoryRestResource(collectionResourceRel = "{id}", path = "phone")
public interface PhoneRepository extends JpaRepository<Phone, Long> {

    Collection<Phone> findByPersonLastName(@Param("name") String name);

}

最后是Application类：

import org.springframework.boot.SpringApplication;
import org.springframework.boot.autoconfigure.SpringBootApplication;

@SpringBootApplication
public class Application {

    public static void main(String[] args) {
        SpringApplication.run(Application.class, args);

    }

}

现在，当我使用Postman运行jar时，我可以使用URL来获取，发布，删除和删除Person实体，例如，

(POST) http://localhost:8080/people/

体

{"firstName":"Jack", "lastName":"Brown"}

但是，当我尝试在以下人员的情况下为手机发布POST时：

(Post) http://localhost:8080/people/5/phones

体

{"homePhone":"24102234", "workPhone":"9831299878"}

我得到的答复如下：

{
  "timestamp": 1443796964061,
  "status": 405,
  "error": "Method Not Allowed",
  "exception": "org.springframework.web.HttpRequestMethodNotSupportedException",
  "message": "Request method 'POST' not supported",
  "path": "/people/5/phones"
}

如果有人能帮我解决这个问题，我将不胜感激。

谢谢，普拉纳

@OneToMany - 不支持请求方法“POST”

0 个答案: