Question

我有一个包含4列Id, Date, Material, Amount的表格。

示例数据如下所示：

--------------------------------------------
   Id    |    Date    | Material|   Amount  
--------------------------------------------
   1     | 01/01/2013 |  1      |    500   
   2     | 01/01/2013 |  2      |    400  
   3     | 01/01/2013 |  1      |    200  
   4     | 02/01/2013 |  1      |    600    
   5     | 02/01/2013 |  2      |    200   
   6     | 03/01/2013 |  2      |    100    
   7     | 04/01/2013 |  1      |    800     
   8     | 05/01/2013 |  2      |    400   
   9     | 06/01/2013 |  1      |    800     
   10    | 06/01/2013 |  2      |    700   
   11    | 06/01/2013 |  1      |    600

我需要编写一个查询来获得如下结果：

-----------------------------------------------
    Date    | Material  |   DailyAmount | Total 
-----------------------------------------------
 01/01/2013 |    1      |    700        |  700
 02/01/2013 |    1      |    400        |  1100
 04/01/2013 |    1      |    800        |  1900
 06/01/2013 |    1      |    1400       |  3300

Dailyamount是日期中Amount的总和。我只想选择Material = 1。 Total字段是DailyAmount的总和，直到那天。我搜索得很多，但我无法得到任何关于此的信息......

Answer 1

您可以使用sum函数的分析（窗口）变体来获取运行总计。应使用常规聚合sum）来完成每日总和：

SELECT [date], [material], [DailyAmount], 
       SUM([DailyAmount]) OVER (ORDER BY [date]
                                ROWS BETWEEN UNBOUNDED PRECEDING AND 
                                             CURRENT ROW) AS [Total]
FROM   (SELECT   [date], material, SUM([amount] AS [DailyAmount]
        FROM     my_table
        WHERE    material = 1
        GROUP BY [date], material) t

Answer 2

SQL Fiddle Demo

WITH CTE AS
(
    SELECT DATE1,MATERIAL,SUM(AMOUNT) AS AMOUNT
    FROM DATA
    GROUP BY DATE1,MATERIAL
)
SELECT DATE1,MATERIAL,SUM(AMOUNT) OVER(ORDER BY DATE1)
FROM CTE
WHERE MATERIAL=1

其他方式..

WITH CTE AS
(
    SELECT DATE1,MATERIAL,SUM(AMOUNT) AS AMOUNT ,ROW_NUMBER() OVER(PARTITION BY MATERIAL ORDER BY DATE1) AS RN
    FROM DATA
    GROUP BY DATE1,MATERIAL
),
 CTE1 AS
(
    SELECT DATE1,MATERIAL,AMOUNT,RN FROM CTE WHERE RN=1
    UNION ALL
    SELECT  C2.DATE1,C2.MATERIAL,C1.AMOUNT+C2.AMOUNT,C2.RN 
    FROM CTE1 C1
            INNER JOIN CTE C2 ON C1.RN+1 = C2.RN AND C1.MATERIAL = C2.MATERIAL          
)
SELECT * FROM CTE1 ORDER BY MATERIAL,DATE1

Answer 3

可以使用CROSS JOIN和;with cte as ( select rn = row_number() over ( order by [date] ),[Date],Material,sum(Amount) as Amount from myTable where Material = 1 group by [Date],Material ) select t1.[Date],t1.Material,t1.Amount as DailyAmount, sum(t2.Amount) as Total from cte t1 cross join cte t2 where t2.rn <= t1.rn group by t1.[Date],t1.Material,t1.Amount;来实现此目的。

<强>查询

urljoin()

SQL Fiddle

Answer 4

 ;WITH CTE AS
   (
    SELECT
      [Date]   
     ,Material  
     ,SUM(Amount)  DailyAmount

   FROM
   YourTable
   WHERE 
   Material = 1
   GROUP BY
    [Date]    
   ,Material  
    )

    SELECT 
     A.[Date]
    ,A.Material
    ,A.DailyAmount
    ,SUM(B.DailyAmount)
    FROM CTE A
    INNER JOIN
    CTE B
    ON
    B.[Date]<=A.[Date]
    GROUP BY
     A.[Date]
    ,A.Material
    ,A.DailyAmount

如何编写查询以显示列值的总和并显示在旁边？

4 个答案: