这是我的toString()函数,它位于超类中。 我希望能够在我的子类中重用此函数,但将其修改为" Trapezoid的坐标"而不是"四边形的坐标"。
我尝试过使用stringbuilder来修改返回值,但它没有用,所以也许我误用了stringbuilder。我想做的是什么,或者我应该将整个方法的代码复制/粘贴到我的子类方法中并修改那里的文本?
public String toString(){ //this function returns a readable view of our quadrilateral object
String message = new String();
message = "Coordinates of Quadrilateral are:\n< " + this.point1.getX() + ", " + this.point1.getY() + " >, < "
+ this.point2.getX() + ", " + this.point2.getY() + " >, < "
+ this.point3.getX() + ", " + this.point3.getY() + " >, < "
+ this.point4.getX() + ", " + this.point4.getY() + " >\n";
return message;
}
这是我的子类
//this function returns a readable view of our trapezoid
public String toString(){
String modify = super.toString();
StringBuilder sb = new StringBuilder(modify);
sb.replace(16, 28, "Trapezoid");
return modify + "\nHeight is: " + getHeight() + "\nArea is: " + getArea();
}
答案 0 :(得分:1)
而不是
return modify + "\nHeight is: " + getHeight() + "\nArea is: " + getArea();
试
return sb.toString() + "\nHeight is: " + getHeight() + "\nArea is: " + getArea();
BTW,而不是+
,最好使用StringBuilder.append()
,就像这样
String modify = super.toString();
StringBuilder sb = new StringBuilder(modify);
sb.replace(16, 28, "Trapezoid");
sb.append("\nHeight is: ").append(getHeight()); // etc.
答案 1 :(得分:1)
比修改超类输出更好的是修改超类,以便子类可以提供适当的形状名称,例如
class Quadrilateral {
protected String getShapeName() {
return "Quadrilateral";
}
public String toString() {
String message = "Coordinates of " + getShapeName() + ...
...
}
}
class Trapezoid {
@Override
protected String getShapeName() {
return "Trapezoid";
}
}
主要的好处是你可以摆脱Trapezoid toString()对超类&#39;的确切措辞的依赖性。的toString()。想象一下,您将Quadrilateral的toString()消息更改为&#34; Quadrilateral的坐标...&#34; - 如果你这样做,你必须修改Trapezoid中的索引(16,28)(或者可能是其他子类),或者它的toString()将打印&#34; coordinatesTrapezoideral ...& #34;
答案 2 :(得分:0)
使用
return sb.toString() + "\nHeight is: " + getHeight() + "\nArea is: " + getArea();