Question

编写查询以打印以元音开头的CITY列表（a，e，我，o，u）按字典顺序排列。不要打印重复项。

我的解决方案：

Select DISTINCT(City)
From Station
Where City like 'A%' 
   or City like 'E%' 
   or City like 'I%' 
   or City like 'O%' 
   or City like 'U%'
Order by City;

其他解决方案：

select distinct(city) from station
where upper(substr(city, 1,1)) in ('A','E','I','O','U');

这非常聪明，但我想知道，有没有其他方法可以解决这个问题？

任何类型的数据库都可以。

Answer 1

MySQL / MariaDB中的正则表达式：

select distinct city from station where city regexp '^[aeiouAEIOU]' order by city

Answer 2

在SQLserver中您可以使用类似注册的语法：

select distinct city from station where city like '[aeuio]%' Order by City

Answer 3

在SQL Server中

select distinct city from station 
 where charindex ('a',CITY) =1
    or charindex ('e',CITY) =1
    or charindex ('i',CITY) =1
    or charindex ('o',CITY) =1
    or charindex ('u',CITY) =1

具有多个值的通配符？

3 个答案: