使用Spring Security在Grails 3.0.4中进行基本身份验证

Question

我尝试使用Grails 3.0和AngularJS进行基本身份验证。

首先在$sql = "SELECT check_pass('test123','123456')"; $connection = ConnectionManager::get('default'); $results = $connection->execute($sql)->fetchAll('assoc'); 我添加了Spring Security插件（http://grails-plugins.github.io/grails-spring-security-core/guide/index.html）：

build.gradle

然后我配置了 compile 'org.grails.plugins:spring-security-core:3.0.0.M1'

application.yml

在角度服务中，我创建了这个方法：

grails:
  plugin:
    springsecurity:
      useBasicAuth: true
      basic:
        realmName: "xxx"
      userLookup:
        userDomainClassName: xxx
      rejectIfNoRule: true
      fii:
        rejectPublicInvocations: false
      controllerAnnotations:
        staticRules: [... ommited ...]

在模块confid中，我添加了var authenticateOwner = function (credentials, callback) { var headers = credentials ? {authorization: "Basic " + btoa(credentials.username + ":" + credentials.password)} : {}; $http.get('/login/owner', {headers: headers}).success(function (data) { $rootScope.authenticated = !!data.basicUserInfo.name; callback && callback(); }).error(function () { $rootScope.authenticated = false; callback && callback(); }); }; 标头，以防止X-Requested-With回来：

WWW-Authenticate

问题在于，我得到angular.module([...]).config(function ($httpProvider) { $httpProvider.defaults.headers.common["X-Requested-With"] = 'XMLHttpRequest'; }); 标题，使浏览器显示登录对话框。 那么我如何才能正确登录AngulrJS＆amp; Grails的？

PS 我使用本教程：https://spring.io/guides/tutorials/spring-security-and-angular-js/在Grails中开发登录。