在MySQL

时间:2015-10-02 10:21:45

标签: php mysql sql lookup poker

我想为扑克手的组合创建一个查找表。 7卡板中有1.13亿种不同的手部组合。

如果我给每张卡片上一个数字(1-52)并希望将每种可能的组合存储在表格中,那么最好的方法是什么呢?我希望它能快速查找,所以如果我有一只手13,18,1,51,38,8,49,我可以搜索表格中的行。

我可以将每张卡存储在自己的列中,如下所示:

poker_hands (id, card1, card2, card3, card4, card5, card6, card7)

或者我可以为7张牌创建某种哈希值,如:

$string= md5($card1 . $card2 . $card3 . $card4 . $card5 . $card6. $card7);

然后使用它来查找手

poker_hands (id, hash) 

(我也会在数据库中存储有关每只手的等级的信息;但是现在我只想知道创建查找表的最佳方法。)

1 个答案:

答案 0 :(得分:0)

首先创建一个从1到52的数字列表。您可以这样做:

create table numbers as
    select 1 as n union all select 2 union all . . .;

或者,从已经存在的表开始:

create table numbers as
    select (@rn := @rn + 1) as n
    from t
    limit 52;

然后,使用交叉连接创建组合:

create table hands as
    select n1.n as card1, n2.n as card2, n3.n as card3, n4.n as card4,
           n5.n as card5, n6.n as card6, n7.n as card7
    from numbers n1 cross join
         numbers n2 cross join
         numbers n3 cross join
         numbers n4 cross join
         numbers n5 cross join
         numbers n6 cross join
         numbers n7;

这可能是数据库中最快的方法。

编辑:

如果卡片不同,则放入适当的条件:

create table hands as
    select n1.n as card1, n2.n as card2, n3.n as card3, n4.n as card4,
           n5.n as card5, n6.n as card6, n7.n as card7
    from numbers n1 join
         numbers n2
         on n2.n not in (n1.n) join
         numbers n3
         on n3.n not in (n1.n, n2.n) join
         numbers n4
         on n4.n not in (n1.n, n2.n, n3.n) join
         numbers n5
         on n5.n not in (n1.n, n2.n, n3.n, n4.n) join
         numbers n6
         on n6.n not in (n1.n, n2.n, n3.n, n4.n, n5.n) join
         numbers n7
         on n7.n not in (n1.n, n2.n, n3.n, n4.n, n5.n, n6.n);