我刚刚完成了我的网络作业队列,我对Java中PriortiyQueue的性能提出了一些小问题。
拿这段代码:
private void performJob() {
lock.lock();
try {
NetworkJob job = actions.poll();
if (job.perform()) {
return;
}
actions.add(job); //Job was a failure, add it back to the queue
} finally {
lock.unlock();
}
}
如果作业失败,则作业仍然需要在队列中。所以,我的问题是:poll()
然后add()
或peek()
然后remove()
我个人倾向于下面的代码,但考虑到工作不应该真的失败(在大多数情况下,假设它是一个通行证)仅仅poll()
更好吗?
private void performJob() {
lock.lock();
try {
NetworkJob job = actions.peek();
if (!job.perform()) {
return;
}
actions.remove(); //Job was a success, we can remove it from the queue.
} finally {
lock.unlock();
}
}
完全挑剔,可能不值得担心由于队列中很少使用的性质,但它让我感兴趣,我希望看到你的推理。
完整代码:
import android.content.BroadcastReceiver;
import android.content.Context;
import android.content.Intent;
import android.content.IntentFilter;
import android.net.ConnectivityManager;
import android.net.NetworkInfo;
import android.util.Log;
import java.util.PriorityQueue;
import java.util.concurrent.atomic.AtomicBoolean;
import java.util.concurrent.locks.Condition;
import java.util.concurrent.locks.ReentrantLock;
public final class NetworkQueue implements Runnable {
private final Context context;
private final AtomicBoolean running = new AtomicBoolean(true);
private final PriorityQueue<NetworkJob> actions = new PriorityQueue<>(5, new NetworkJobComparator());
private final ReentrantLock lock = new ReentrantLock();
private final Condition jobReady = lock.newCondition();
private final Condition networkUp = lock.newCondition();
private ConnectionType connection = ConnectionType.NONE;
public NetworkQueue(Context context) {
this.context = context;
context.registerReceiver(new NetworkListener(),
new IntentFilter(ConnectivityManager.CONNECTIVITY_ACTION));
}
@Override
public void run() {
try {
while (running.get()) {
waitJobAvailable();
waitNetworkUp();
performJob();
}
} catch (InterruptedException e) {
e.printStackTrace();
}
}
private void setNetwork(ConnectionType net) {
lock.lock();
try {
connection = net;
if (connection != ConnectionType.NONE) {
networkUp.signal();
}
} finally {
lock.unlock();
}
}
private void waitNetworkUp() throws InterruptedException {
lock.lock();
try {
while (connection != ConnectionType.NONE) {
networkUp.await();
}
} finally {
lock.unlock();
}
}
private void waitJobAvailable() throws InterruptedException {
lock.lock();
try {
while (actions.isEmpty()) {
jobReady.await();
}
} finally {
lock.unlock();
}
}
private void performJob() {
lock.lock();
try {
NetworkJob job = actions.peek();
if (!job.perform()) {
return;
}
actions.remove();
} finally {
lock.unlock();
}
}
public boolean addJob(NetworkJob job) {
lock.lock();
try {
if (this.actions.contains(job)) {
return false;
}
this.actions.add(job);
this.jobReady.signal();
return true;
} finally {
lock.unlock();
}
}
public void end() {
this.running.set(false);
}
private class NetworkListener extends BroadcastReceiver {
ConnectivityManager conn = (ConnectivityManager)
context.getSystemService(Context.CONNECTIVITY_SERVICE);
@Override
public void onReceive(Context context, Intent intent) {
NetworkInfo networkInfo = conn.getActiveNetworkInfo();
if (networkInfo == null) {
setNetwork(ConnectionType.NONE);
return;
}
if (networkInfo.getType() == ConnectivityManager.TYPE_WIFI) {
setNetwork(ConnectionType.WIFI);
return;
}
setNetwork(ConnectionType.ANY);
}
}
}
答案 0 :(得分:1)
在OpenJDK和OracleJDK的标准基于堆的PriorityQueue
实现中,peek()
调用非常快:
public E peek() {
return (size == 0) ? null : (E) queue[0];
}
那是因为堆根始终是最少的元素。相反,删除和添加操作可能非常昂贵,因为它们可能需要重组堆。因此,peek/remove
解决方案可能会更快。
在我的库中,我有一个算法可以从未排序的输入中选择n
个最少的元素。我使用PriorityQueue
实现了它,它最多保留了迄今为止发现的最少n
个元素。第一个实现就像add/poll
。当我updated使用peek
时,性能得到了显着提升(在某些测试中最高可达10倍)。