Question

我在使用XQuery生成字符串组时遇到问题。每个连接都会添加一个接一个的空白区域。

例如，我的XML文件就像这样

<createRequest>
    <transactionType>GAME1</transactionType>
    <listOfBoard>
        <board>
            <gameType>RegularA</gameType>
            <listOfBoardData>
                <boardData>6</boardData>
                <boardData>12</boardData>
            </listOfBoardData>
        </board>
        <board>
            <gameType>RegularB</gameType>
            <listOfBoardData>
                <boardData>7</boardData>
                <boardData>8</boardData>
                <boardData>11</boardData>
                <boardData>21</boardData>
                <boardData>28</boardData>
                <boardData>47</boardData>
            </listOfBoardData>
        </board>
    </listOfBoard>
    <ticketPrice>600</ticketPrice>
</createRequest>

我的代码

let $requestMessage := //createRequest

let $boardData := 
for $eachOfListBoardData in 1 to count($requestMessage/listOfBoard/board/listOfBoardData)
return
   fn:concat(fn:string-join($requestMessage/listOfBoard/board[$eachOfListBoardData]/listOfBoardData/boardData, ","),":")


return $boardData

但结果是在每个组之后输出额外的空格，如下所示

6,12: 7,8,11,21,28,47: 4,11,21,26,28,31: 7,28,31,45,46,49: 15,29,34,36,41,42: 5,7,14,21,42,46:

并且在数字'46'之后添加'：'

我想要的输出是6,12:7,8,11,21,28,47:4,11,21,26,28,31:7,28,31,45,46,49:15,29,34,36,41,42:5,7,14,21,42,46

任何想法？

Answer 1

＆＃34; ...但结果是在每个组之后输出额外的空格...＆＃34;

string-join()传递空字符串作为第二个参数可以帮助您解决这个问题。

＆＃34;它正在添加＆＃39;：＆＃39;在数字＆＃39; 46＆＃39;＆＃34;
之后

只有当前项目不是最后一项时，您才可以使用if-else构造来附加:，请参阅下面的完整XQuery示例：

let $requestMessage := //createRequest
let $lastBoard := ($requestMessage/listOfBoard/board/listOfBoardData)[last()]

let $boards := 
for $board in $requestMessage/listOfBoard/board/listOfBoardData
return
    if($board is $lastBoard)
        then fn:string-join($board/boardData, ",")
    else fn:concat(fn:string-join($board/boardData, ","),":")

let $boardData := fn:string-join($boards, "")

return $boardData

XQuery生成连接但添加额外的空白字符

1 个答案: