Question

我创建了两个定制的marshal_load和marshal_dump方法来排除一个无法编组的特定实例变量。我使用了this问题中的建议。

我现在正在尝试从文件中编写和读取编组对象。这是原始代码

class MarshalTest
  include MarshalUtils
  attr_reader :foo, :bar, :baz

  def initialize(foo = nil, bar = nil, baz = nil)
    @log = File.open('test.log', 'w' )
    @foo = foo
    @bar = bar
    @baz = baz
    @log.close
  end

end

module MarshalUtils
  def marshal_dump
    instance_variables.reject{|m| m == :@log}.inject({}) do |vars, attr|
      vars[attr] = instance_variable_get(attr)
      vars
    end
  end

  def marshal_load(vars)
    vars.each do |attr, value|
      instance_variable_set(attr, value) unless attr == :@log
    end
  end
end

模块MarshalUtils创建并读取字符串。我如何转换它以便写入和读取二进制文件，因为我的对象非常大？这是我的尝试

module MarshalUtils2
  def marshal_dump
    dump = instance_variables.reject{|m| m == :@log}.inject({}) do |vars, attr|
      vars[attr] = instance_variable_get(attr)
      vars
    end
    File.open('dump.marshal', 'wb') do |f|
      f.write(dump)
    end
  end

  def marshal_load(vars)
    vars.each do |attr, value|
      instance_variable_set(attr, value) unless attr == :@log
    end
  end
end

File.write是否实际创建了二进制文件？如果是，我该如何阅读并重新创建原始对象？

Bespoke Marshal和二进制写/读

0 个答案: