Question

我有两个以下类型的列表：

C=[[a1,b1,c1,a2,c2],[d1,e1,f1,d2,f2]]

我希望能够像这样生成一个列表C：

ES_READONLY

有什么想法吗？

Answer 1

您可以使用zip()函数获取列，然后使用collections.OrderedDict保留前一个订单中的唯一元素：

>>> from collections import OrderedDict
>>> d=OrderedDict()
>>> [d.fromkeys(i+j).keys() for i,j in zip(A,B)]
[['a1', 'b1', 'c1', 'a2', 'c2'], ['d1', 'e1', 'f1', 'd2', 'f2']]

Answer 2

此解决方案不需要排序也不需要索引

a = 0
b = 0
c = 0
d = 0
e = 0
f = 0
g = 0
h = 0

def loop():
    Bit = 7
    Numbers = [a, b, c, d, e, f, g, h];
    Num = 128
    Input = int(input("What Number do you want to convert?" ))

    while Input > 0:
        if Input > Num:
            Input = Input - Num
            Numbers[Bit] = 1
        else:
            Numbers[Bit] = 0

        Bit = Bit - 1
        Num = Num/2
    Numbers = str(Numbers)
    print (Numbers)

loop()

它产生

C = [ea+[e for e in eb if e not in ea] for ea,eb in zip(A,B)]

Answer 3

作为列表理解：

import operator
c = [sorted(list(set(a + b)), key=operator.itemgetter(1, 0)) for a, b in zip(A, B)]

或作为循环：

import operator
results = []
for a, b in zip(A, B):
    uniques = list(set(a + b))
    # Here we do two sorts in one call:
    results.append(sorted(uniques, key=operator.itemgetter(1, 0)))

print(results)

[['a1', 'b1', 'c1', 'a2', 'c2'], ['d1', 'e1', 'f1', 'd2', 'f2']]

Answer 4

C = []
# zip the lists to be able to loop through both
# at the same time.
# make from A and B sets to be able to make a union of 
# A and B. Convert the union set to list to sort it and
# to append to the main list
for i, (m, n) in enumerate(zip(A,B)):
  C.append(sorted(list(set(A[i]) | set(B[i]))))

 print(C)

**output**

[['a1', 'a2', 'b1', 'c1', 'c2'], ['d1', 'd2', 'e1', 'f1', 'f2']]

Python列表列表比较

4 个答案: