Question

我有一种情况，我在报告服务器中有一个已部署的rdl文件。有问题的rdl文件有一个参数。

我正在使用rs.exec组件来执行报告;每当我从rdl文件中删除参数时，我都成功地从存储过程运行报告。当我添加参数时，我不断得到的是

\\server\R\subfolder\working\inputfile\example.batK00WE is not recognized as an internal or external operable program or batch file.

这是我做的：我在VB中创建了一个.rss文件（请参阅下面的代码）

 Public Sub Main()

    TRY

     DIM historyID as string = Nothing
     DIM deviceInfo as string = Nothing
     DIM extension as string = Nothing
     DIM encoding as string
     DIM mimeType as string = "application/Excel"
     DIM warnings() AS Warning = Nothing
     DIM streamIDs() as string = Nothing
     DIM results() as Byte

     rs.Credentials = System.Net.CredentialCache.DefaultCredentials
     rs.LoadReport(REPORTSERVER_FOLDER, historyID)

     results = rs.Render(FORMAT, deviceInfo, extension, mimeType, encoding, warnings, streamIDs)

     DIM stream As FileStream = File.OpenWrite(FILENAME)
     stream.Write(results, 0, results.Length)
     stream.Close()

    Catch e As IOException
      Console.WriteLine(e.Message)
    End Try
End Sub

之后......我写了一个使用rs.exec的批处理文件。请参阅以下内容：

"\\server\R\subfolder\working\app\rs.exe" -i \\server\R\subfolder\working\inputfile\coo.rss -s "http://server/ReportServer_MSSQLSERVER2" -v FILENAME="\\server\R\subfolder\working\inputfile\file.csv" -v REPORTSERVER_FOLDER="/FILE_REPORT/FILE" -t  -v FORMAT="EXCEL" -e Exec2005

如果您看到上面的脚本，则rs.exec使用报表服务器的路径等。

最后，我创建了一个存储过程，它将在服务器上运行报告并将参数值传递给服务器。

CREATE PROCEDURE [dbo].[test_sproc]
@ProcessID varchar(50)

AS

DECLARE @cmdsql varchar(1000)
Declare @id  varchar(50)
Set     @id=@SID
Set     @cmdsql= '"\\server\R\subfolder\working\inputfile\example.bat"' + @id
exec master..xp_CMDShell @cmdsql

所以我的问题是：如何将参数值从存储过程传递到报表服务器？我的代码在哪里出错？

通过存储的procudure

0 个答案: