Question

如何在try-catch外获取变量x，y和z？

这是我的代码：

public static void mudarSpawn_1(GtaPlayer player, string coordenadas)
{
    char[] delimiterChars = { ' ', ',' };
    string text = coordenadas;
    string[] words = text.Split(delimiterChars);
    try
    {
         float x = float.Parse(words[0], System.Globalization.CultureInfo.InvariantCulture);
         float y = float.Parse(words[1], System.Globalization.CultureInfo.InvariantCulture);
         float z = float.Parse(words[1], System.Globalization.CultureInfo.InvariantCulture);
    }
    catch (Exception e)
    {
        player.SendClientMessage(Color.DarkOrange, "Os valores de x,y e z não foram inseridos de forma correcta, apenas podes usar numeros");
        player.SendClientMessage(Color.DarkOrange, "Ex: /mudarspawn3 6321.6 , 96321.38 , 66322.2 ou /mudarspawn3 6321.6 96321.38 66322.2");
    }

    MSGameMysql.mudarspawn1(x, y, z);
    player.SendClientMessage(Color.AliceBlue, "Acabaste de mudar o spawn 1 para: x='" + x + "' y='" + y + "' z='" + z + "'");
}

MSGameMysql.mudarspawn1(x, y, z);
player.SendClientMessage(Color.AliceBlue, "Acabaste de mudar o spawn 1 para: x='" + x + "' y='" + y + "' z='" + z + "'");

这个x y和z变量在mudarspawn1（）内变回x = 0 y = 0且z = 0

我该如何解决这个问题？

我试着做一套但得到......但没有幸福的结局。

主要用途是：玩家写/ mudarspawn1 [coordenadas]

Ex：/ mudarspawn1 656.32 65.21 698.1

但如果他们使用字符，程序将收到错误，我想向他们发送聊天，告诉他们只能使用数字。

Answer 1

您必须在try范围之前声明并初始化它们：

    float x = 0f;
    float y = 0f;
    float z = 0f;
    try
    {
         x = float.Parse(words[0], System.Globalization.CultureInfo.InvariantCulture);
         y = float.Parse(words[1], System.Globalization.CultureInfo.InvariantCulture);
         z = float.Parse(words[1], System.Globalization.CultureInfo.InvariantCulture);
    }
    catch (Exception e)
    {
        player.SendClientMessage(Color.DarkOrange, "Os valores de x,y e z não foram inseridos de forma correcta, apenas podes usar numeros");
        player.SendClientMessage(Color.DarkOrange, "Ex: /mudarspawn3 6321.6 , 96321.38 , 66322.2 ou /mudarspawn3 6321.6 96321.38 66322.2");
    }

    MSGameMysql.mudarspawn1(x, y, z);
    player.SendClientMessage(Color.AliceBlue, "Acabaste de mudar o spawn 1 para: x='" + x + "' y='" + y + "' z='" + z + "'");

但是，您最好不要在float.TryParse()查看，也不要在此处使用异常处理（这可能会给您带来不良后果）。例如，

float x;
if (!float.TryParse(words[0], NumberStyles.AllowThousands || NumberStyles.Float, System.Globalization.CultureInfo.InvariantCulture, out x))
{
   // unable to parse words[0] as a float, handle it here.
}

Answer 2

如何在try-catch外获取变量x，y和z？

在try...catch之外声明它们，但将它们设置在其中，例如。

float x = 0f; 
float y = 0f;
float z = 0f;
try
{
     x = float.Parse(...);
     y = float.Parse(...);
     z = float.Parse(...);
}
catch (Exception e)
{
    ...
}

Answer 3

您需要在外面声明它们并在内部协助它们

float x;
float y;
float z;

try
{
   x = float.Parse(words[0], System.Globalization.CultureInfo.InvariantCulture);
   y = float.Parse(words[1], System.Globalization.CultureInfo.InvariantCulture);
   z = float.Parse(words[1], System.Globalization.CultureInfo.InvariantCulture);
 }
....

Answer 4

以下是您要查找的代码，

        public static void mudarSpawn_1(GtaPlayer player, string coordenadas)
        {
            char[] delimiterChars = { ' ', ',' };
            string text = coordenadas;
            string[] words = text.Split(delimiterChars);
            float x = new float();
            float y = new float();
            float z = new float();
            try
            {
                x = float.Parse(words[0], System.Globalization.CultureInfo.InvariantCulture);
                y = float.Parse(words[1], System.Globalization.CultureInfo.InvariantCulture);
                z = float.Parse(words[1], System.Globalization.CultureInfo.InvariantCulture);
            }
            catch (Exception e)
            {
                player.SendClientMessage(Color.DarkOrange, "Os valores de x,y e z não foram inseridos de forma correcta, apenas podes usar numeros");
                player.SendClientMessage(Color.DarkOrange, "Ex: /mudarspawn3 6321.6 , 96321.38 , 66322.2 ou /mudarspawn3 6321.6 96321.38 66322.2");
            }

            MSGameMysql.mudarspawn1(x, y, z);
            player.SendClientMessage(Color.AliceBlue, "Acabaste de mudar o spawn 1 para: x='" + x + "' y='" + y + "' z='" + z + "'");


        }

Answer 5

谢谢你们！它的工作我在mudarspawn1（）中使用了一个if来处理来自xy或z的0

public static void mudarspawn1(GtaPlayer player, float x, float y, float z)
    {

        if (x == 0 || y == 0 || z == 0)
        {


        }
        else
        {

            string sql = "update spawnposition set spawn_1x = '" + x + "', spawn_1y = '" + y + "', spawn_1z = '" + z + "' where id ='1'";

            try
            {

                MySqlConnection conn = new MySqlConnection(cs);
                conn.Open();

                MySqlCommand cmd1 = new MySqlCommand(sql, conn);
                cmd1.ExecuteNonQuery();
                player.SendClientMessage(Color.DarkOrange, "Foi adicionado o spawn 1");


            }
            catch (MySqlException e)
            {



            }
        }

修正：D

c＃在外面尝试并捕获+变量

5 个答案: