程序在尝试从文件中获取字符串并访问字符串中的单个字母时崩溃

时间:2015-10-01 09:07:50

标签: c string loops pointers file-handling

我正在创建一个C程序,将所有小写转换为大写,反之亦然。在C程序中,我试图从文本文件中获取一个字符串并访问每个字符。但我的程序崩溃了。我在这里做的错误是什么?以下是我的代码:

 //Program to read contents from a source file and convert the lower case characters to a upper case and vice versa and print it on a target file

#include <stdio.h>
#include <stdlib.h>

void merge(FILE *fp,int n,char *fdata,FILE *fpr)
{
    char change_case[1000];
    int loop = 0;

    while(fgets(fdata,n,fp)!=NULL)
    {
        fgets(fdata,n,fp);

        //printf("%s",fdata);

        if ((*(fdata+loop) >= 65) && (*(fdata+loop) <= 90))
        {
            printf("%c",*(fdata+loop));
            change_case[loop] = *(fdata+loop)+32;
        }
        else if ((*(fdata+loop) >= 97) && ((*fdata+loop) <= 122))
        {
            printf("%c",*(fdata+loop));
            change_case[loop] = *(fdata+loop)-32;
        }
        else
        {
            change_case[loop] = *(fdata+loop);
        }
        loop++;

        fpr = fopen("Text File 3.dat","w");

        if (fpr == NULL)
        {
            printf("Error in accessing / writing the target file"); 
        }
        else
        {
            fputs(change_case,fpr);
            printf("Line written successfully : %s\n", change_case);
        }
    }
}

int main()
{
    FILE *sfp, *tfp; //declaring a file pointer for source file and target file
    char *fdata;
    int n = 1000;
    sfp = fopen("Text File 1.txt","r");

    if (sfp == NULL)
    {
        printf("Error in reading the source file\n");
    }

    else
    {
        merge(sfp,n,fdata,tfp);
    }   

    fclose(sfp);

return 0;
}

1 个答案:

答案 0 :(得分:1)

在功能void merge(FILE *fp,int n,char *fdata,FILE *fpr) -

fgets(fdata,n,fp);         // you tend to write at invalid location 

内存未分配给fdata。你需要为它分配内存。

fdata=malloc(n);     // check its return and also remember to free it

注意 - 不要使用while!feof(fp)

你可以这样做 -

while(fgets(fdata,n,fp)!=NULL)
{
     // your code
}